颤振溢出定位的按钮不可单击 [英] Flutter overflowed positioned Button is not clickable

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本文介绍了颤振溢出定位的按钮不可单击的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我有一个堆栈小部件,其父元素是这样的定位部件:

I have a stack widget parenting a Positioned widget like this:

Stack(
        overflow: Overflow.visible,
        children: [
          Container(
            width: 150,
            height: 150,
          ),
          Positioned(
            child: FloatingActionButton(
              child: Icon(Icons.add),
              onPressed: () {
                print('FAB tapped!');
              },
              backgroundColor: Colors.blueGrey,
            ),
            right: 0,
            left: 0,
            bottom: -26,
          ),
        ],
      ),

位于晶圆厂外部的晶圆厂部分不可点击,解决方案是什么?
,这是屏幕截图:

That part of the fab which is placed outside the container is not clickable, what is the solution? and here is a screenshot:

推荐答案

尝试一下:

      Stack(
        overflow: Overflow.visible,
        children: [
          Column(
            mainAxisSize: MainAxisSize.min,
            children: <Widget>
            [
              Container(width: 150, height: 150, color: Colors.yellow),
              Container(width: 150, height: 28, color: Colors.transparent),
            ],
          ),
          Positioned(
            child: FloatingActionButton(
              child: Icon(Icons.add),
              onPressed: () {
                print('FAB tapped!');
              },
              backgroundColor: Colors.blueGrey,
            ),
            right: 0,
            left: 0,
            bottom: 0,
          ),
        ],
      )

如果希望按钮保持可点击状态,则应将按钮保留在堆栈中

you should keep button inside of stack if you want it to stay clickable

这篇关于颤振溢出定位的按钮不可单击的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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