如何按时间间隔连接2个数据表并按因子变量汇总重叠和不重叠的时间段 [英] How to join 2 data tables by time interval and summarize overlapping and non-overlapping time periods by factor variable

问题描述

我有2个数据表，每个数据表都列出了观察工作量的周期以及工作量的类型（A，B，C）。
我想知道工作重叠和不重叠的持续时间。

I have 2 data tables, each lists periods of observation effort, and type of effort (A,B,C). I would like to know the duration of time for the overlapping and non-overlapping periods of effort.

我尝试使用data.table来做到这一点。和foverlaps，但无法弄清楚如何包括所有非重叠时间段。

I've tried to do this with data.table and foverlaps, but can't figure out how to include all the non-overlapping periods.

这是我的示例数据。我首先创建了2个包含工作时间的数据表。我的数据集将包括一个观察者在努力的时间段。

Here is my example data. I first created 2 data tables containing periods of effort. My dataset will include periods of time when a single observer is on effort.

library(data.table)
library(lubridate)

# times have been edited so not fixed to minute intervals - to make more realistic
set.seed(13)
EffortType = sample(c("A","B","C"), 100, replace = TRUE)
On = sample(seq(as.POSIXct('2016/01/01 01:00:00'), as.POSIXct('2016/01/03 01:00:00'), by = "1 sec"), 100, replace=F)
Off = On + minutes(sample(1:60, 100, replace=T))
Effort1 = data.table(EffortType, On, Off)

EffortType2 = sample(c("A","B","C"), 100, replace = TRUE)
On2 = sample(seq(as.POSIXct('2016/01/01 12:00:00'), as.POSIXct('2016/01/03 12:00:00'), by = "1 sec"), 100, replace=F)
Off2 = On2 + minutes(sample(1:60, 100, replace=T))
Effort2 = data.table(EffortType2, On2, Off2)

#prep for using foverlaps
setkey(Effort1, On, Off)
setkey(Effort2, On2, Off2)

然后我用护腿板找到工作重叠的地方。我设置了nomatch = NA，但这给了我正确的外部连接。我想要完整的外部连接。所以我想知道更合适的功能是什么。

Then I use foverlaps to find where the effort overlaps. I've set nomatch=NA, but this just gives me the right outer join. I would like the full outer join. And so i wonder what the more appropriate function would be.

matches = foverlaps(Effort1,Effort2,type="any",nomatch=NA)

我在这里继续说明如何确定持续时间所有重叠和不重叠的移位时间。但是我也不认为这部分内容正确。

I've continued on here to show how I've tried to determine the duration of all the overlapping and non-overlapping shift times. But I don't think I've got this part correct either.

# find start and end of intersection of all shifts
matches$start = pmax(matches$On, matches$On2, na.rm=T)
matches$end = pmin(matches$Off, matches$Off2, na.rm=T)

# create intervals and find durations
matches$int = interval(matches$start, matches$end)
matches$dur = as.duration(matches$int)

然后我想总结每个 EffortType分组的观察工作时间量

I would then like sum up the amount of observation effort time for each grouping of "EffortType"

最后得到这样的结果（数字仅是示例，因为即使在excel中，我也无法弄清楚如何正确计算该值）

And end up with something like this (numbers are examples only because I have not managed to figure out how to calculate this correctly, even in excel)

EffortType  Duration(in minutes)
A           10
B           20
C           12
AA          8
BB          6
CC          1
AC          160
AB          200
BC          150

推荐答案

不是全部答案（请参阅最后一段）。但是我认为这会为您提供所需的内容。

Not the entire answer (see last paragraph).. but I think this will get you what you want.

library( data.table )
library( lubridate )

set.seed(13)
EffortType = sample(c("A","B","C"), 100, replace = TRUE)
On = sample(seq(as.POSIXct('2016/01/01 01:00:00'), as.POSIXct('2016/01/03 01:00:00'), by = "15 mins"), 100, replace=T)
Off = On + minutes(sample(1:60, 100, replace=T))
Effort1 = data.table(EffortType, On, Off)

EffortType2 = sample(c("A","B","C"), 100, replace = TRUE)
On = sample(seq(as.POSIXct('2016/01/01 12:00:00'), as.POSIXct('2016/01/03 12:00:00'), by = "15 mins"), 100, replace=T)
Off = On + minutes(sample(1:60, 100, replace=T))
Effort2 = data.table(EffortType2, On, Off)

#create DT of minutes, spanning your entire period.
dt.minutes <- data.table( On = seq(as.POSIXct('2016/01/01 01:00:00'), as.POSIXct('2016/01/03 12:00:00'), by = "1 mins"), 
                          Off = seq(as.POSIXct('2016/01/01 01:00:00'), as.POSIXct('2016/01/03 12:00:00'), by = "1 mins") + 60 )

#prep for using foverlaps
setkey(Effort1, On, Off)
setkey(Effort2, On, Off)

#overlap join both efforts on the dt.minutes. note the use of "within" an "nomatch" to throw away minutes without events.

m1 <- foverlaps(dt.minutes, Effort1 ,type="within",nomatch=0L)
m2 <- foverlaps(dt.minutes, Effort2 ,type="within",nomatch=0L)

#bind together
result <- rbindlist(list(m1,m2))[, `:=`(On=i.On, Off = i.Off)][, `:=`(i.On = NULL, i.Off = NULL)]

#cast the result
result.cast <- dcast( result, On + Off ~ EffortType, value.var = "EffortType")

结果

head( result.cast, 10)

#                      On                 Off A B C
#  1: 2016-01-01 01:00:00 2016-01-01 01:01:00 1 0 1
#  2: 2016-01-01 01:01:00 2016-01-01 01:02:00 1 0 1
#  3: 2016-01-01 01:02:00 2016-01-01 01:03:00 1 0 1
#  4: 2016-01-01 01:03:00 2016-01-01 01:04:00 1 0 1
#  5: 2016-01-01 01:04:00 2016-01-01 01:05:00 1 0 1
#  6: 2016-01-01 01:05:00 2016-01-01 01:06:00 1 0 1
#  7: 2016-01-01 01:06:00 2016-01-01 01:07:00 1 0 1
#  8: 2016-01-01 01:07:00 2016-01-01 01:08:00 1 0 1
#  9: 2016-01-01 01:08:00 2016-01-01 01:09:00 1 0 1
# 10: 2016-01-01 01:09:00 2016-01-01 01:10:00 1 0 1

有时事件发生2-3在同一分钟内的时间，例如

Sometimes a event occurs 2-3 times within the same minute, like

#                     On                 Off A B C
#53: 2016-01-02 14:36:00 2016-01-02 14:37:00 2 2 3

不确定您想要的方式总结一下...

Not sure on how you want to sum that...

如果您可以将它们视为一分钟，则：

If you can treat them as a single minute, then:

> sum( result.cast[A>0 & B==0, C==0, ] )
[1] 476
> sum( result.cast[A==0 & B>0, C==0, ] )
[1] 386
> sum( result.cast[A==0 & B==0, C>0, ] )
[1] 504
> sum( result.cast[A>0 & B>0, C==0, ] )
[1] 371
> sum( result.cast[A==0 & B>0, C>0, ] )
[1] 341
> sum( result.cast[A>0 & B==0, C>0, ] )
[1] 472
> sum( result.cast[A>0 & B>0, C>0, ] )
[1] 265

可以在数分钟内完成持续时间的技巧，我想（尽管这可以用更聪明的方式完成）

will do the trick to get duration in minutes, I think (although this can probably be done in a much smarter way)

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