动态分配data.table tstrsplit中的拆分数 [英] dynamically assign number of splits in data.table tstrsplit

问题描述

在 data.table v.1.9.6 中，您可以按以下方式在列中拆分变量：

In data.table v.1.9.6 you can split a variable in columns like so:

library(data.table)
DT = data.table(x=c("A/B", "A", "B"), y=1:3)
DT[, c("c1", "c2") := tstrsplit(x, "/", fixed=TRUE)][]

并非总是预先知道所需的分割数[以上：2]。
已知拆分数时如何生成所需的变量名？

The number of required splits [above: 2] is not always known in advance. How can I generate the required variable names when the number of splits is known?

n = 2  # desired number of splits
# naive attempt to build required string
m = paste0("'", "myvar", 1:n, "'", collapse = ",")
m = paste0("c(", m, ")" )

# [1] "c('myvar1','myvar2','myvar3')"


DT[, m := tstrsplit(x, "/", fixed=TRUE)][]  # doesn't work

推荐答案

两个方法。强烈建议第一个：

Two methods. The first is strongly suggested:

#one
n=2
DT[, paste0("myvar", 1:n) := tstrsplit(x, "/", fixed=T)][]
#     x y myvar1 myvar2
#1: A/B 1      A      B
#2:   A 2      A     NA
#3:   B 3      B     NA

#two
DT[, eval(parse(text=m)) := tstrsplit(x, "/", fixed=TRUE)][]
#     x y myvar1 myvar2
#1: A/B 1      A      B
#2:   A 2      A     NA
#3:   B 3      B     NA 

额外

如果您事先不知道拆分的数量，则：

If you do not know the amount of splits beforehand:

splits <- max(lengths(strsplit(DT$x, "/")))
DT[, paste0("myvar", 1:splits) := tstrsplit(x, "/", fixed=T)][]

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