摆脱然后Angularjs承诺 [英] Break Out of then promises in Angularjs

问题描述

我试图找到一种方法，打破了在AngularJS code诺言链。最明显的办法是返回一个对象，然后检查的有效性是在链的每一个，那么功能。

I am trying to find a way to break out of a promise chain in AngularJS code. The obvious way was to return an object and then check is validity in every "then" function in the chain.

我想找到一个那么链的突破更优雅的方式。

I would like to find a more elegant way of breaking out of a then chain.

推荐答案

在棱角分明，有可以在指令注入了$ Q服务，控制器等，也就是克里斯·科瓦尔的Q的接近implentation
所以，那么里面的函数，而不是返回将被链接到下一个thenable功能的值或别的东西，只返回一个 $ q.reject（拒绝的理由'）;

In angular, there is the $q service that can be injected in directives, controllers etc, that is a close implentation of Kris Kowal's Q. So inside of then function instead of returning a value or something else that would be chained to the next "thenable" function, just return a $q.reject('reject reason');

例如：

angular.module('myQmodule',[])
.controller('exController',['$q',function($q){
  //here we suppose that we have a promise-like function promiseFunction()
  promiseFunction().then(function(result1){
    //do the check we want in order to end chain
    if (endChainCheck) {
      return $q.reject('give a reason');
    }
    return;
  })
  .then(function(){
  //this will never be entered if we return the rejected $q
  })
  .catch(function(error){
   //this will be entered if we returned the rejected $q with error = 'give a reason'
  });
}]);

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