按行而不是列取消列出数据框 [英] Unlist a data frame by rows, not columns

问题描述

一个相对简单的问题，但是答案似乎使我难以理解。当前，我有一个类似于以下内容的数据框：

A relatively simple question, but the answer seems to have eluded me. Currently, I have a data frame which looks similar to this:

0   0   0   1   1
0   1   0   1   1
2   1   1   0   3

我正在尝试将其变成一行数据（按行）。我使用了 unlist 函数，它实现了我想要的功能，但是按列将其提供给我。它给了我这个：

I'm trying to turn this into a single line of data, by rows. I used the unlist function, and it did what I wanted, but gave them to me by columns. It gave me this:

0,0,2,0,1,1,0,0,1,1,1,0,1,1,3

但是我想要的是：

0,0,0,1,1,0,1,0,1,1,2,1,1,0,3

我很抱歉，这似乎是一个愚蠢的问题，但我仍然是R的新手。任何帮助（或

I apologize if this seems like a silly question, but I'm still a novice with R. Any help (or referrals to functions which might help me process this) would be greatly appreciated.

推荐答案

我们可以进行转置（ t ），然后使用 c 获得矢量输出

We can take the transpose (t) of the dataset and then use c to get a vector output

 c(t(df1))
 #[1] 0 0 0 1 1 0 1 0 1 1 2 1 1 0 3

通过转置，我们将'data.frame'转换为'matrix'。在 data.frame 或 matrix 中， unlist / c 操作按列进行。因此，转置将列换为行，反之亦然，我们得到了预期的结果。

By doing transpose, we convert the 'data.frame' to 'matrix'. In both data.frame or matrix, unlist/c operations happen columnwise. So, transposing swaps the columns for rows and viceversa and we get the expected result.

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