棱角分明的UI用户界面路由器 - 使用多个嵌套视图 [英] Angular-ui ui-router - using multiple nested views

问题描述

我想出来的UI插件路由器的嵌套视图功能，但遇到我不知道如何解决这个问题。
在code，显示问题可以在 http://jsfiddle.net/3c9h7/1/ <找到/ A>

I am trying out the nested views feature of ui-router plugin, but faced the issue I don't know how to solve. The code that shows the problem can be found at http://jsfiddle.net/3c9h7/1/ :

  var app = angular.module('myApp', ['ui.router']);

  app.config(function($stateProvider) {
    return $stateProvider.state('root', {
      template: "<div class='top' ui-view='viewA'></div><div class='middle' ui-view='viewB'></div>"
    }).state('root.step1', {
      url: '',
      views: {
        'viewA': {
          template: '<h1>View A</h1>'
        }
      }
    }).state('root.step1.step2', {
      url: '/step2',
      views: {
        'viewB': {
          template: '<h1>View B</h1>'
        }
      }
    });
  });

  app.controller('MainCtrl', [
    '$scope', '$state', function($scope, $state) {
      $state.transitionTo('root.step1.step2');
    }
  ]);

<div ng-app='myApp' ui-view ng-controller='MainCtrl'>
</div>

因此​​，code。通过使用$ state.go法（的https://github.com/angular-ui/ui-router/wiki/Quick-Reference#stategoto--toparams--options)
据UI路由器文档：

So, the code activates "root.step1.step2" state by using $state.go method(https://github.com/angular-ui/ui-router/wiki/Quick-Reference#stategoto--toparams--options) According to ui-router documentation:

在该应用程序是在一个特定的状态时的状态
  激活它的祖先状态 - 所有的隐式主动为好。

When the application is in a particular state—when a state is "active"—all of its ancestor states are implicitly active as well.

所以，我希望root.step1和根将被激活，它工作正常，但viewB是不是充满了模板，你可以的jsfiddle样品中看到：上面viewA（根。步骤1）是确定的，但中间viewB（root.step1.step2）为空。
我做错了吗？

So, I expect that "root.step1" and "root" will be active and it works as expected, but "viewB" is not filled with the template as you can see in jsfiddle sample : the top viewA(root.step1) is OK, but the middle viewB(root.step1.step2) is empty. What I am doing wrong?

推荐答案

该文件说：

儿童国家将他们的模板加载到其父母的UI视图。

Child states will load their templates into their parent's ui-view.

所以应该有一个用户界面视图='viewB'的viewA模板内，由于母公司状态 root.step1.step2 是 root.step1 。或者viewB应该是 root.step1 的意见之一，不应该有 root.step1.step2

So there should be a ui-view='viewB' inside the viewA template, since the parent state of root.step1.step2 is root.step1. Or the viewB should be one of the views of root.step1, and there should be no root.step1.step2.

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