日期差小于一个值的总和 [英] Sum if the date difference is smaller than a value
本文介绍了日期差小于一个值的总和的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我有一个数据库,其中包含一系列机器的错误记录及其对应的日期。有几种错误。即:
fechayhora id tipo
1:2017-03-21 11:03:00 A2_LR1_Z1 APF
2:2017-05-03 10:34:00 A2_LR1_Z1 APF
3:2017-05-17 08:52:00 A2_LR1_Z1 APF
4:2017-05-17 10:46:00 A2_LR1_Z1 APF
5:2017-05-17 14:23:00 A2_LR1_Z1 APF
6:2017-05-17 17:29:00 A2_LR1_Z1 APF
我要添加一列,该列包含先前发生的尖锐 APF事件的总和,可以说12个小时(实际上,可能会有所不同。)
预期结果:
fechayhora id tipo number_of_APF_12h
1:2017-03-21 11:03:00 A2_LR1_Z1 APF 0
2:2017-05-03 10:34:00 A2_LR1_Z1 APF 0
3:2017-05-17 08 :52:00 A2_LR1_Z1 APF 0
4:2017-05-17 10:46:00 A2_LR1_Z1 APF 1
5:2017-05-17 14:23:00 A2_LR1_Z1 APF 2
6 :2017 -05-17 17:29:00 A2_LR1_Z1 APF 3
解决方案
这里是一种利用 purrr :: map2_dbl()
的解决方案。您可以将小时数更改为所需的小时数。
< pre $ class $$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$$创建了一个压缩包。 b preventPackageStartupMessages(library(lubridate))
#示例数据
df<-tribble(
〜fechayhora,〜id,〜tipo,
2017-03 -21 11:03:00, A2_LR1_Z1, APF,
2017-05-03 10:34:00, A2_LR1_Z1, APF,
2017-05 -17 08:52:00, A2_LR1_Z1, APF,
2017-05-17 10:46:00, A2_LR1_Z1, APF,
2017-05 -17 14:23:00, A2_LR1_Z1, APF,
2017-05-17 17:29:00, A2_LR1_Z1, APF
)
#将fechayhora转换为日期并添加一列时差
df<-df%&%;%
mutate(fechayhora = as.POSIXct(fechayhora),
minus_12 = fechayhora-小时(12))
#映射fechayh ora和minus_12
#对于每个(fechayhora,minus_12)对,找到它们之间的所有日期
#并对返回的逻辑向量求和
df<-df%>%mutate (
number_of_APF_12h = map2_dbl(.x = fechayhora,
.y = minus_12,
.f =〜sum(between(df $ fechayhora,.y,.x))-1))
df%>%
select(fechayhora,number_of_APF_12h)
#> #小动作:6 x 2
#> fechayhora number_of_APF_12h
#> < dttm> < dbl>
#> 1 2017-03-21 11:03:00 0
#> 2 2017-05-03 10:34:00 0
#> 3 2017-05-17 08:52:00 0
#> 4 2017-05-17 10:46:00 1
#> 5 2017-05-17 14:23:00 2
#> 6 2017-05-17 17:29:00 3
I have a database that contains the registers of errors of a series of machines, with their correspondent date. There are several kind of errors. Ie:
fechayhora id tipo
1: 2017-03-21 11:03:00 A2_LR1_Z1 APF
2: 2017-05-03 10:34:00 A2_LR1_Z1 APF
3: 2017-05-17 08:52:00 A2_LR1_Z1 APF
4: 2017-05-17 10:46:00 A2_LR1_Z1 APF
5: 2017-05-17 14:23:00 A2_LR1_Z1 APF
6: 2017-05-17 17:29:00 A2_LR1_Z1 APF
I would to add a column that contains the sum of the events tipye "APF" that have occured in the previous, lets say 12 hours (a parameter actually that I could vary).
Result expected:
fechayhora id tipo number_of_APF_12h
1: 2017-03-21 11:03:00 A2_LR1_Z1 APF 0
2: 2017-05-03 10:34:00 A2_LR1_Z1 APF 0
3: 2017-05-17 08:52:00 A2_LR1_Z1 APF 0
4: 2017-05-17 10:46:00 A2_LR1_Z1 APF 1
5: 2017-05-17 14:23:00 A2_LR1_Z1 APF 2
6: 2017-05-17 17:29:00 A2_LR1_Z1 APF 3
解决方案
Here is a solution that utilizes purrr::map2_dbl()
. You can change the number of hours to whatever you'd like.
suppressPackageStartupMessages(library(tibble))
suppressPackageStartupMessages(library(dplyr))
suppressPackageStartupMessages(library(purrr))
suppressPackageStartupMessages(library(lubridate))
# Example data
df <- tribble(
~fechayhora, ~id, ~tipo,
"2017-03-21 11:03:00", "A2_LR1_Z1", "APF",
"2017-05-03 10:34:00", "A2_LR1_Z1", "APF",
"2017-05-17 08:52:00", "A2_LR1_Z1", "APF",
"2017-05-17 10:46:00", "A2_LR1_Z1", "APF",
"2017-05-17 14:23:00", "A2_LR1_Z1", "APF",
"2017-05-17 17:29:00", "A2_LR1_Z1", "APF"
)
# Convert fechayhora to date and add a column of the time difference
df <- df %>%
mutate(fechayhora = as.POSIXct(fechayhora),
minus_12 = fechayhora - hours(12))
# Map over fechayhora and minus_12
# For each (fechayhora, minus_12) pair, find all the dates between them
# and sum the logical vector that is returned
df <- df %>% mutate(
number_of_APF_12h = map2_dbl(.x = fechayhora,
.y = minus_12,
.f = ~sum(between(df$fechayhora, .y, .x)) - 1))
df %>%
select(fechayhora, number_of_APF_12h)
#> # A tibble: 6 x 2
#> fechayhora number_of_APF_12h
#> <dttm> <dbl>
#> 1 2017-03-21 11:03:00 0
#> 2 2017-05-03 10:34:00 0
#> 3 2017-05-17 08:52:00 0
#> 4 2017-05-17 10:46:00 1
#> 5 2017-05-17 14:23:00 2
#> 6 2017-05-17 17:29:00 3
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