在for循环上的pandas isin函数 [英] pandas isin function on a for loop
问题描述
1.csv
cut price depth carat table
0 Good 327 57.9 0.23 65.0
1 Good 335 63.3 0.31 58.0
2 Very Good 336 62.8 0.24 57.0
3 Very Good 336 62.3 0.24 57.0
4 Very Good 337 61.9 0.26 55.0
5 Premium 326 59.8 0.21 61.0
6 Premium 334 62.4 0.29 58.0
7 Good 400 64.0 0.30 55.0
2.csv
cut price depth carat table
0 Good 327 57.9 0.23 65.0
1 Good 335 63.3 0.31 58.0
2 Very Good 336 62.8 0.24 57.0
3 Very Good 336 62.3 0.24 57.0
4 Very Good 337 61.9 0.26 50.0
5 Premium 326 59.8 0.21 61.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
仅2、4、6、7行.csv已更改
only 4,6,7 rows from 2.csv is changed
我希望获得
像这样的输出
cut price depth carat table
4 Very Good 337 61.9 0.26 50.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
任何人都可以分享您的经验吗?
can anyone share your experience any kind of help is fine
import pandas as pd
f1 = pd.read_csv('1.csv')
f2 = pd.read_csv('2.csv')
columns_list = ['cut', 'price', 'depth', 'carat', 'table']
new_df= f2[~f2.price.isin(f1.price)]
print(new_df)
这是我编写的示例代码,它工作正常,但我需要使用
this is a sample code i wrote and it's working fine but i need to use the
f2 [〜f2.price.isin(f1.price)]
f2[~f2.price.isin(f1.price)]
循环获取该价格空间上的每个列名称,这也将返回该值。
in a loop to get each columns name on that 'price' space and also that will return the value.i tried in normal way like this
for i in columns_list:
price = f2[~f2.i.isin(f1.i)]
print(price)
但是pandas命令是不能像这样工作,它会返回错误,例如
but pandas command is not work with like this way it's return an error like
AttributeError: 'DataFrame' object has no attribute 'i'
感谢您的阅读,希望您能理解
Thankz for reading, i hope you understand this
推荐答案
IIUC, DataFrame.merge
与 indicator = True
:
IIUC, DataFrame.merge
with indicator = True
:
f2_filtered = (f2.merge(f1, how='outer', indicator=True)
.query('_merge == "left_only"')
.drop(columns = '_merge'))
print(f2_filtered)
输出
cut price depth carat table
4 Very_Good 337 61.9 0.26 50.0
6 Premium 334 60.4 0.29 58.0
7 Good 399 64.0 0.30 55.0
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