如何使用datetime在python中获取给定日期的下个月的同一天 [英] how to get the same day of next month of a given day in python using datetime

问题描述

我知道使用datetime.timedelta可以从给定日期获得几天的日期

i know using datetime.timedelta i can get the date of some days away form given date

daysafter = datetime.date.today() + datetime.timedelta(days=5)

但似乎没有 datetime.timedelta（month = 1）

推荐答案

当然没有-如果今天的1月31日是下个月的同一天？显然，没有 right 解决方案，因为2月31日不存在，并且 datetime 模块不会不在猜出没有适当解决方案而提出这个不可能的问题的用户认为（错误地）是显而易见的解决方案；-）。

Of course there isn't -- if today's January 31, what would be "the same day of the next month"?! Obviously there is no right solution, since February 31 does not exist, and the datetime module does not play at "guess what the user posing this impossible problem without a right solution thinks (wrongly) is the obvious solution";-).

我建议：

try:
  nextmonthdate = x.replace(month=x.month+1)
except ValueError:
  if x.month == 12:
    nextmonthdate = x.replace(year=x.year+1, month=1)
  else:
    # next month is too short to have "same date"
    # pick your own heuristic, or re-raise the exception:
    raise

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