以C语言中的日期为dd / mm / yy [英] taking date as dd/mm/yy in c language

问题描述

    # include <stdio.h>
int main(){
    int d1, d2, m1, m2, year;
    printf("Enter date (dd/mm/yy): ");
    scanf("%d,%d/%d,&,d/%d", &d1,&d2,&m1,&m2,&year);

**大家好，我是c编程新手，所以我尝试将日期设为dd / mm / yy格式，但是当我这样写时，它为19/07/14输入提供了191/033/0的输出，我该如何解决呢？ **

**Hello guys I am new in c programming so I'm trying to take the date as dd/mm/yy format but when I write it like this it gives me an output as 191/033/0 for 19/07/14 input how can i fix this? **

推荐答案

# include <stdio.h>
int main(){
    int d, m, year;
    printf("Enter date (dd/mm/yy): ");
    scanf("%d/%d/%d", &d,&m,&year);
    if (d%10==1 && d!=11) printf("%d st",d);
    else if (d%10==2 && d!=12) printf("%d nd",d);
    else if (d%10==3 && d!=13) printf("%d rd",d);
    else printf("%d th",d);
    return 0;
}

顺便说一下， dd / mm / yy 不是的意思是两天零两个月零。这表示日，月和年的两位数字。这就是为什么您不需要那么多变量的原因。

By the way, dd/mm/yy does not mean 'two days, two months and two years'. This means 'two digits for day, month and year'. That's why you don't need so many variables.

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