如何避免任何时间（<数字>）“通过引用更新”？ [英] How to avoid that anytime(<numeric>) "updates by reference"?

问题描述

我想使用随时将数值变量转换为 POSIXct 。我的问题是 anytime（< numeric>）也会转换输入变量-我想保留它。

I want to convert a numeric variable to POSIXct using anytime. My issue is that anytime(<numeric>) converts the input variable as well - I want to keep it.

简单示例：

library(anytime)
t_num <- 1529734500
anytime(t_num)
# [1] "2018-06-23 08:15:00 CEST"
t_num
# [1] "2018-06-23 08:15:00 CEST"

这不同于 as.POSIXct的未按引用更新行为基中的code> R：

This differs from the 'non-update by reference' behaviour of as.POSIXct in base R:

t_num <- 1529734500
as.POSIXct(t_num, origin = "1970-01-01")
# [1] "2018-06-23 08:15:00 CEST"
t_num
# 1529734500

---

类似地， anydate（<数字>）也通过引用进行更新：

---

Similarly, anydate(<numeric>) also updates by reference:

d_num <- 17707
anydate(d_num)
# [1] "2018-06-25"
d_num
# [1] "2018-06-25"

---

我在中找不到对此行为的明确描述any ime 。我可以像上面那样使用 as.POSIXct ，但是有人知道如何在 内随时处理吗？

---

I can't find an explicit description of this behaviour in ?anytime. I could use as.POSIXct as above, but does anyone know how to handle this within anytime?

推荐答案

您可以像这样破解它：

library(anytime)
t_num <- 1529734500
anytime(t_num+0)
# POSIXct[1:1], format: "2018-06-23 08:15:00"
t_num
# [1] 1529734500

整数输入将被不同地对待：

Note that an integer input will be treated differently:

t_int <- 1529734500L
anytime(t_int)
# POSIXct[1:1], format: "2018-06-23 08:15:00"
t_int
# [1] 1529734500

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