从datetime中提取时间并确定时间（而非日期）是否在范围内？ [英] Extract time from datetime and determine if time (not date) falls within range?

问题描述

问题是我希望它忽略日期，只考虑时间。这是我的东西：

The problem is that I want it to ignore the date and only factor in the time. Here is what I have:

import time
from time import mktime
from datetime import datetime

def getTimeCat(Datetime):
    # extract time categories
    str_time = datetime.strptime(Datetime, "%m/%j/%y %H:%M")
    ts = datetime.fromtimestamp(mktime(str_time))

    # --> Morning = 0400-1000
    mornStart = datetime.time(4, 0, 1)
    mornEnd = datetime.time(10, 0, 0)

    # --> Midday = 1000-1600
    midStart = datetime.time(10, 0, 1)
    midEnd = datetime.time(16, 0, 0)

    # --> Evening = 1600-2200
    eveStart = datetime.time(16, 0, 1)
    eveEnd = datetime.time(22, 0, 0)

    # --> Late Night = 2200-0400
    lateStart = datetime.time(22, 0, 1)
    lateEnd = datetime.time(4, 0, 0)

    if time_in_range(mornStart, mornEnd, ts):
      timecat = 0 #morning
    elif time_in_range(midStart, midEnd, ts):
      timecat = 1 #midday
    elif time_in_range(eveStart, eveEnd, ts):
      timecat = 2 #evening
    elif time_in_range(lateStart, lateEnd, ts):
      timecat = 3 #late night

    return timecat

按原样，我会收到此错误：

As is, I get this error:

TypeError: argument must be 9-item sequence, not datetime.datetime

何时我将相关行更改为：

When I change the relevant line to:

str_time = time.strptime(Datetime, "%m/%j/%y %H:%M")

我收到此错误：

TypeError: descriptor 'time' requires a 'datetime.datetime' object but received a 'int'

我知道我很担心拥有两个或两个不同库的国王，但我不确定如何在它们之间进行转换或仅使用一个库就能完成我想做的事情。我只希望它忽略日期，只检查时间是否在指定范围内。

I know I'm working with two different libraries or whatnot, but I'm not sure how to convert between them or accomplish what I want to do only using one. I just want it to ignore the date and only check if the time is within the specified ranges. Python 2.6 is a MUST due to a library I'm using elsewhere in the code.

推荐答案

此行：

str_time = datetime.strptime(Datetime, "%m/%j/%y %H:%M")

返回 datetime 对象根据文档。

您可以通过在解释器中交互式运行以下命令来自己进行测试：

You can test this yourself by running the following command interactively in the interpreter:

>>> import datetime
>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M")
datetime.datetime(2013, 1, 31, 0, 12)
>>>

然后可以使用 .time访问返回日期时间的时间部分。 （）方法。

>>> datetime.datetime.strptime('12/31/13 00:12', "%m/%j/%y %H:%M").time()
datetime.time(0, 12)
>>>

datetime.time（）结果可以然后用于时间比较。

The datetime.time() result can then be used in your time comparisons.

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