Python strptime解析年无世纪：假设在今年之前？ [英] Python strptime parsing year without century: assume prior to this year?

问题描述

我正在使用 datetime.strptime 在Python 2.7中解析一些日期时间字符串。我想假设一个日期早于现在。

I am parsing some datetime strings in Python 2.7, using datetime.strptime. I want to assume that a date is prior to now.

但是strptime的 ％y 运算符默认情况下不会执行此操作：

But strptime's %y operator does not do this by default:

d = '10/12/68'
n = datetime.strptime(d, '%d/%m/%y')
print n
2068-12-10 00:00:00

有什么方法可以让Python假定 68 是 1968 ，因为它很常见？

Is there any way I can get Python to assume that 68 is 1968, as it would be in common usage?

还是我应该只解析字符串并酌情手动插入 19 或 20 吗？

Or should I just parse the string and insert 19 or 20, as appropriate, manually?

推荐答案

以下事实很容易解决：

from datetime import datetime, timedelta
dt = datetime.strptime(...)
if dt > datetime.now():
    dt -= timedelta(years=100)

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