Python：获得所有月份范围？ [英] Python: get all months in range?

问题描述

我想获取从现在到2010年8月之间的所有月份，列表格式如下：

I want to get all months between now and August 2010, as a list formatted like this:

['2010-08-01', '2010-09-01', .... , '2016-02-01']

现在这就是我所拥有的：

Right now this is what I have:

months = []
for y in range(2010, 2016):
    for m in range(1, 13):
        if (y == 2010) and m < 8:
            continue
        if (y == 2016) and m > 2:
            continue
        month = '%s-%s-01' % (y, ('0%s' % (m)) if m < 10 else m)
        months.append(month)

有什么更好的方法？

推荐答案

dateutil .relativedelta 在这里很方便。

dateutil.relativedelta is handy here.

我已将格式保留为练习。

I've left the formatting out as an exercise.

from dateutil.relativedelta import relativedelta
import datetime

result = []

today = datetime.date.today()
current = datetime.date(2010, 8, 1)    

while current <= today:
    result.append(current)
    current += relativedelta(months=1)

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