在Java中的两个工作日之间获取分钟 [英] Get minutes between two working days in Java
问题描述
我正在尝试计算Java中两个Joda DateTimes或Calendars之间的分钟。
当然,如果我可以使用Minutes.minutesBetween函数,这将很简单,但是我只能计算工作日和8:00 AM-6:00 PM之间的分钟数。
I am trying to calculate the minutes between two Joda DateTimes or Calendars in Java. Ofcourse this would be simple if I could use the Minutes.minutesBetween function, but I can only count the minutes between working days and 8:00 AM - 6:00 PM.
例如:
开始日期:2015年3月11日16:00
结束日期:03- 2015年11月11日17:00
Startdate: 03-11-2015 16:00
Enddate: 03-11-2015 17:00
这很简单,因为它恰好是60分钟。因为这是一个工作日,介于给定的工作时间之间。
This would be simple, as it would be exactly 60 minutes. Because it's a workday and between the given work hours.
现在我要计算的是:
开始日期:2015/3/11 17:00
结束日期:2015/03/12 09:00
Startdate: 03-11-2015 17:00
Enddate: 03-12-2015 09:00
这应该返回120分钟,即使它们之间有更多的分钟,因为两个日期之间只有两个工作小时。
This should return 120 minutes even though there's a lot more minutes in between, because there's only two working hours between the two dates.
有时也是两个日期之间的一个周末,也不应添加这些分钟。
Sometimes there's also a weekend between two dates, those minutes should not be added either.
我一直在不懈地努力实现这一目标,但是我没有找到解决方案。
I have been trying tirelessly to implement this, but I have not found a solution.
有什么想法吗?
预先感谢。
编辑:
由于戴维斯·布罗达(Davis Broda)的伪代码,我找到了一个解决方案:
Thanks to Davis Broda's pseudocode I have found a solution:
private static int BEGINWORKHOUR = 8;
private static int ENDWORKHOUR = 16;
public int getWorkedMinutes(){
Calendar start = (Calendar) this.startTime.clone();
Calendar end = (Calendar) this.endTime.clone();
if(start.get(Calendar.HOUR_OF_DAY) < BEGINWORKHOUR){
start.set(Calendar.HOUR_OF_DAY, BEGINWORKHOUR);
start.set(Calendar.MINUTE, 0);
}
if(end.get(Calendar.HOUR_OF_DAY) >= ENDWORKHOUR){
end.set(Calendar.HOUR_OF_DAY, ENDWORKHOUR);
end.set(Calendar.MINUTE, 0);
}
int workedMins = 0;
while(!sameDay(start, end)){
workedMins += workedMinsDay(start);
start.add(Calendar.DAY_OF_MONTH, 1);
start.set(Calendar.HOUR_OF_DAY, BEGINWORKHOUR);
start.set(Calendar.MINUTE, 0);
}
workedMins += (end.get(Calendar.MINUTE) - start.get(Calendar.MINUTE)) + ((end.get(Calendar.HOUR_OF_DAY) - start.get(Calendar.HOUR_OF_DAY))*60);
return workedMins;
}
private int workedMinsDay(Calendar start){
if((start.get(Calendar.DAY_OF_WEEK) == 1) || (start.get(Calendar.DAY_OF_WEEK) == 6)) return 0;
else return (60 - start.get(Calendar.MINUTE)) + ((ENDWORKHOUR - start.get(Calendar.HOUR_OF_DAY) - 1)*60);
}
private boolean sameDay(Calendar start, Calendar end){
if(start.get(Calendar.YEAR) == end.get(Calendar.YEAR) && start.get(Calendar.MONTH) == end.get(Calendar.MONTH) &&
start.get(Calendar.DAY_OF_MONTH) == end.get(Calendar.DAY_OF_MONTH)) return true;
else return false;
}
推荐答案
伪代码解决方案可能看起来像像下面这样。
a pseudocode solution might look something like the below.
onSameWorkDay?
if yes
simple date comparison
if no
days = find number of whole work days between the two dates
dayToMin = days * 8 * 60
minDay1 = find minutes between specified start time and end of day1
minDay2 = find minutes between start of final day and specified end time
totalTime = dayToMin + minDay1 + minDay2
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