在Python中将十进制时间（HH.HHH）转换为HH：MM：SS [英] Converting decimal time (HH.HHH) into HH:MM:SS in Python

问题描述

我有这种格式的小时数，

I have hours in this format,

72.345, 72.629, 71.327, ...

在Python中执行计算的结果。似乎将它们转换为HH：MM：SS格式的最简单方法是使用datetime模块，如下所示：

as a result of performing a calculation in Python. It seems that the simplest way to convert these into HH:MM:SS format is using the datetime module like this:

time = str(datetime.timedelta(seconds = 72.345*3600))

但是，返回的值是天，我不希望这样做：

However, that returns a values with days, which I don't want:

'3 days, 0:20:42'

这是我的大脑得出我想要的最终值的最佳方法：

This is the best way my brain came up with the final values I want:

str(int(math.floor(time))) + ':' + str(int((time%(math.floor(time)))*60)) + ':' + str(int(((time%(math.floor(time)))*60) % math.floor(((time%(math.floor(time)))*60))*60))

这太长了，可能没有必要。但这确实给了我想要的答案：

Which is ridiculously long and probably unnecessary. But it does give me the answer I want:

'72:20:41'

还有更好的方法吗？

推荐答案

您不必使用 datetime 。您可以轻松地从小数点开始计算小时，分钟和秒。

You do not have to use datetime. You can easily compute hours, minutes and seconds from your decimal time.

您还应该注意，可以使用字符串格式，它比字符串串联更容易使用。 / p>

You should also notice that you can use string formatting which is really easier to use than string concatenation.

time = 72.345

hours = int(time)
minutes = (time*60) % 60
seconds = (time*3600) % 60

print("%d:%02d.%02d" % (hours, minutes, seconds))
>> 72:20:42

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