如何在R中以小时为单位找到两个日期之间的差异？ [英] How to find the difference between two dates in hours in R?

问题描述

冒着被问到显而易见的问题而被降低的极高风险，我如何找到两个小时中R中两个日期之间的差异？

At the extreme risk of being modded down for asking "obvious" questions, how do I find the difference between two dates in hours in R?

> ISOdate(2004,1,6) - ISOdate(2004,1,1)
Time difference of 5 days
> as.POSIXlt(ISOdate(2004,1,6) - ISOdate(2004,1,1))
Error in as.POSIXlt.default(ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1)) : 
  do not know how to convert 'ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1)' to class "POSIXlt"
 > (ISOdate(2004,1,6) - ISOdate(2004,1,1))$year
Error in (ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1))$year : 
  $ operator is invalid for atomic vectors
> (ISOdate(2004,1,6) - ISOdate(2004,1,1))$mon
Error in (ISOdate(2004, 1, 6) - ISOdate(2004, 1, 1))$mon : 
  $ operator is invalid for atomic vectors

推荐答案

使用函数 difftime ，并带有参数 units = hours ：

Use the function difftime, with the argument units="hours":

x <- c(ISOdate(2004,1,6), ISOdate(2004,1,1))
difftime(x[1], x[2], units="hours")
Time difference of 120 hours

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我怎么知道去哪里看？

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How did I know where to look?

好吧，首先看一下您减去两次后得到的对象的结构：

Well, start by looking at the structure of the object you get when you subtract two times:

str(x[1] - x[2])
Class 'difftime'  atomic [1:1] 5
  ..- attr(*, "units")= chr "days"

因此，现在您知道您正在处理 difftime 类。从这里很容易找到帮助：请参见？difftime

So now you know you are dealing with a class of difftime. From here it's easy to find help: See ?difftime

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