pytz 2日期时间的差异，以秒为单位？ （不同时区） [英] pytz difference of 2 datetimes in seconds? (Different time zones)

问题描述

我有2个具有两个不同时区的datetime对象：

I have 2 datetime objects with 2 different time zones:

datetime1 = 18：26：23，tzinfo = UTC

datetime1 = 18:26:23, with tzinfo = UTC

datetime2 = 14:30:00，其中tzinfo =美国/东部

datetime2 = 14:30:00, with tzinfo = US/Eastern

两个日期都在同一天。

两个日期时间之间应该精确地相差1小时，3分钟和37秒，即：3817秒的总时差。

There should be exactly 1 hour, 3 minutes and 37 seconds difference between the 2 datetimes, which is: 3817 seconds total difference.

但是，当我使用以下代码进行比较时：

However, when I use the following code to compare:

time_diff = (datetime2 - datetime1).total_seconds()

time_diff给我一个值：3576。

time_diff gives me a value of: 3576.

我在几秒钟之内做错了吗？还是我不正确地将pytz用于时区？

Am I doing the difference in seconds wrong? Or am I not utilizing pytz for time zones correctly?

非常感谢。

推荐答案

这里有两种可能的情况。

There are two likely scenarios here.

1. 您在日期时间对象上创建的时区不正确


2. 时区正确，但是您的datetime对象实际上并不代表您所说的时间。

例如，无论时区如何，我都看不到 18:26:23 和 14:30:00 之间的时差可能会给你几秒钟的时间，这使场景2的可能性更高。

For example, regardless of timezone, I don't see how the diff between 18:26:23 and 14:30:00 could possibly give you an even number of seconds, which makes scenario #2 more likely.

您可以打印 datetime 对象，然后再运行以下行：

Can you print the value of the datetime objects right before you run the line:

time_diff = (datetime2 - datetime1).total_seconds()

以下是一些示例代码，可为您提供预期的秒数：

Here is some sample code for reference that gives you the expected seconds:

from pytz import timezone
from datetime import datetime

eastern = timezone('US/Eastern')
utc = timezone('UTC')
datetime1 = utc.localize(datetime(2002, 10, 27, 18, 26, 23))
datetime2 = eastern.localize(datetime(2002, 10, 27, 14, 30, 00))
time_diff = (datetime2 - datetime1).total_seconds()
print(time_diff)  # prints 3817

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