在条件之间使用条件从PYTHON datetimerange中的00.00-7.00AM（EST）获取网站的数据 [英] to fetch the data's from website from 00.00 - 7.00AM(EST) IN PYTHON datetimerange using between condition

问题描述

published_date = 7/11/2019 at 06:04 AM,7/11/2019 at 1:04 AM,7/11/2019 at 5:36 AM,7/11/2019 at 04:00 PM

所有时间均为EST。
我需要从 00.00-07.00 AM（EST）的时间范围内获取数据。应跳过 7.00AM（EST）的时间）

All times are in EST. I need to fetch data from time range of 00.00 - 07.00 AM(EST).It should skip the time above 7.00AM(EST)

如果published_date.time（）< = 7:00 AM
print（published_date.time（））

if published_date.time() <= 7:00AM print(published_date.time())

实际结果：

published_date = 7/11/2019 at 06:04 AM,7/11/2019 at 1:04 AM,7/11/2019 at 5:36 AM,7/11/2019 at 04:00 PM

预期结果：

published_date = 7/11/2019 at 06:04 AM,7/11/2019 at 1:04 AM,7/11/2019 at 5:36 AM

推荐答案

您的日期格式不正确。因此，它将无法解析并正确比较它。您需要使用 datetime 库将字符串转换为日期并进行比较。
这是工作示例：

Your date are not in correct format. Hence it will not parse and compare it correct. You need to use datetime library to convert the strings into date and compare. Here is the working example:

from datetime import datetime
import datetime as dt

datetime_object = datetime.strptime('Jun 1 2005  1:33PM', '%b %d %Y %I:%M%p')
checkTime = dt.time(7,0,0)
published_dates = ["7/11/2019 06:04 AM","7/11/2019 1:04 AM","7/11/2019 5:36 AM","7/11/2019 04:00 PM"]
filtered_dates = []
for d in published_dates:
  dt1 = datetime.strptime(d, '%d/%m/%Y %I:%M %p')
  if (dt1.time() < checkTime):
      filtered_dates.append(dt1.strftime("%d/%m/%Y %I:%M %p"))
print('filtered_dates : ', filtered_dates)

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