sqlite添加日期到日期 [英] sqlite adding days to a date

问题描述

我正在尝试编写一个sqlite语句，该语句从表中返回一个日期，并从另一列中添加了一定天数。日期存储为 YYYY-MM-DD HH：mm：ss ，将天数存储为整数。

I'm trying to write an sqlite statement which returns a date from the table with a certain number of days added from another column. The date is stored as YYYY-MM-DD HH:mm:ss and the number of days just as an integer.

我有

SELECT strftime('%Y-%m-%d %H:%M:%S' , 
strftime('%s',transactions.date)+repeattransactions.interval*24*60*60) 
FROM transactions,repeattransactions

但这给年份和各种各样的事物增加了更多的数字。想知道我是否可以得到一些帮助，添加日期并以相同的格式输出？

but this is adding wierd amounts to the years and all sorts. Wonder if I could get some help adding the days and outputting it in the same format?

谢谢。

推荐答案

$ sqlite3
SQLite version 3.7.7 2011-06-23 19:49:22
Enter ".help" for instructions
Enter SQL statements terminated with a ";"
sqlite> create table t (tdate, tinterval);
sqlite> insert into t values ('2011-09-08 11:11:11', 5);
sqlite> select datetime(t.tdate,'+'||t.tinterval||' days') from t;
2011-09-13 11:11:11

请参见 SQLite3日期&时间函数

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