绘制datetime.date大 pandas [英] Plot datetime.date pandas
问题描述
我根据特定日历日期的一些值创建了一个熊猫数据框。这是我的操作方式:
I created a pandas dataframe from some value counts on particular calendar dates. Here is how I did it:
time_series = pd.DataFrame(df['Operation Date'].value_counts().reset_index())
time_series.columns = ['date', 'count']
,它是两列,第一列日期是具有 datetime.date
对象的列,第二列 count只是整数值。
Basically, it is two columns, the first "date" is a column with datetime.date
objects and the second column, "count" are simply integer values.
现在,我想绘制散点图或KDE来表示日历日内的价值变化,但是如何?
Now, I'd like to plot a scatter or a KDE to represent the value changes over the calendar days, but how?
我查看了数据框,所有内容都按顺序排列,完全按照我上面的描述。但是当我尝试:
I looked at the dataframe and it all looks in order and exactly as I describe above. But when I try:
time_series.plot(kind='kde')
plt.show()
我得到一个绘图,其中x轴从-50到150,就好像它在解析 datetime.date
对象以某种方式作为整数。而且,它产生的是两个相同的图,而不仅仅是一个。
I get a plot where the x-axis is from -50 to 150 as if it is parsing the datetime.date
objects as integers somehow. Also, it is yielding two identical plots rather than just one.
任何想法我都可以绘制它们并沿x轴查看日历日吗?
Any idea how I can plot them and see the calendars day along the x-axis?
推荐答案
您确定日期时间?我只是尝试了一下,而且效果很好:
you sure you got datetime? i just tried this and it worked fine:
df = date count
7 2012-06-11 16:51:32 1.0
3 2012-09-28 08:05:14 12.0
19 2012-10-01 18:01:47 4.0
2 2012-10-03 15:18:23 29.0
6 2012-12-22 19:50:43 4.0
1 2013-02-19 19:54:03 28.0
9 2013-02-28 16:08:40 17.0
12 2013-03-12 08:42:55 6.0
4 2013-04-04 05:27:27 6.0
17 2013-04-18 09:40:37 29.0
11 2013-05-17 16:34:51 22.0
5 2013-07-07 14:32:59 16.0
14 2013-10-22 06:56:29 13.0
13 2014-01-16 23:08:46 20.0
15 2014-02-25 00:49:26 10.0
18 2014-03-19 15:58:38 25.0
0 2014-03-31 05:53:28 16.0
16 2014-04-01 09:59:32 27.0
8 2014-04-27 12:07:41 17.0
10 2014-09-20 04:42:39 21.0
df = df.sort_values('date', ascending=True)
plt.plot(df['date'], df['count'])
plt.xticks(rotation='vertical')
编辑:
如果要散点图,可以:
plt.plot(df['date'], df['count'], '*')
plt.xticks(rotation='vertical')
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