ValueError：时间数据与格式'％Y-％m-％d％H：％M：％S.％f'不匹配 [英] ValueError: time data does not match format '%Y-%m-%d %H:%M:%S.%f'
问题描述
我面临一个小问题。我正在存储一些日期时间数据，并且数据是
I am facing one little problem. I am storing some date time data and the data is
# "datetime","numb","temperature"
"1998-04-18 16:48:36.76",0,38
"1998-04-18 16:48:36.8",1,42
"1998-04-18 16:48:36.88",2,23
"1998-04-18 16:48:36.92",3,24
"1998-04-18 16:48:36",4,42
"1998-04-18 16:48:37",5,33
"1998-04-18 16:48:37.08",6,25
日期时间列显然是字符串，因此当我尝试对其进行转换时，出现了此错误
the date time column is clearly string, so when I try to convert it , I got this error
ValueError: time data '1998-04-18 16:48:36' does not match format '%Y-%m-%d %H:%M:
%S.%f'
我的代码是
import time
import datetime
import calendar
for k, line in enumerate(lines):
if k > (int(header_line)):
data_pre = line.strip().split(',')
stDate = data_pre[0].replace("\"", "")
print stDate # got 1998-04-18 16:48:36.76
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
mic_sec = dat_time.microsecond
timcon = calendar.timegm(dat_time.timetuple())*1000000 + mic_sec
strDate = "\"" + strDate + "\""
print stDate # got "1998-04-18 16:48:36.76"
因为我的某些datetime列缺少。％f值，所以出现了此错误，我的文档中可能包含数千个这样的日期时间值，所以我想出了追加解决方案。 0和所有这样的日期时间。因此，如果日期时间字符串为
because some of my datetime column is missing .%f value, so I got this error. my documents might contains a few thousands such date time values, so I came up with solution to append .0 with all such date time. so that if date time string is
"1998-04-18 16:48:36"
我的代码应附加.0以符合格式标准。例如
my code should append .0 to fulfill the format criteria. e.g
"1998-04-18 16:48:36.0"
我尝试将.0附加到stDate，但出现此错误
I try to append .0 to stDate, but I get this error
AttributeError: 'str' object has no attribute 'append'
如果有人给我一个提示如何处理这样的问题。任何帮助将不胜感激。
If somebody gives me a clue how to deal with such a problem. Any help would be greatly appreciated.
推荐答案
更新：我仔细阅读了您的代码，发现了一些错误类型。
此外，您似乎没有添加串联。
Update: I've looked through your code and found some misstypes. In addition, it looks like you didn't add in the concatenation.
我都把它们都解决了。
您写道：
for k, line in enumerate(lines):
if k > (int(header_line)):
data_pre = line.strip().split(',')
stDate = data_pre[0].replace("\"", "")
print stDate # got 1998-04-18 16:48:36.76
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
mic_sec = dat_time.microsecond
timcon = calendar.timegm(dat_time.timetuple())*1000000 + mic_sec
strDate = "\"" + strDate + "\""
# ^ This line is wrong
# It should say:
# strDate = "\"" + stDate + "\""
print stDate # got "1998-04-18 16:48:36.76"
# ^ This line is wrong
# It should say:
# print strDate
实现从头开始更改后，我们现在可以在代码示例中添加 + .0
（尝试先运行此代码，确保您了解它是什么）
Implementing the above changes, we can now add the " + ".0" " addition to a sample of your code
(Try running this first, make sure you understand what it is doing, before moving on):
import time
import datetime
import calendar
A = "1998-04-18 16:48:36.76,0,38"
B = "1998-04-18 16:48:37,5,33"
# Run the Code for B
data_pre = B.strip().split(',')
print data_pre
stDate = data_pre[0].replace("\"", "")
print "stDate before: ", stDate
### Addition of Addition of .0
# Here, we try to convert to datetime format using the format
# '%Y-%m-%d %H:%M:%S.%f'
try:
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
# If that doesn't work, we add ".4" to the end of stDate
# (You can change this to ".0")
# We then retry to convert stDate into datetime format
except:
stDate = stDate + ".4"
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
print "stDate after: ", stDate
###
print "dat_time: ", dat_time
mic_sec = dat_time.microsecond
print "mic_sec: ", mic_sec
timcon = calendar.timegm(dat_time.timetuple())*1000000 + mic_sec
print "timecon: ", timcon
strDate = "\"" + stDate + "\""
print "strDate: ", strDate
因此，例如：
Therefore, for an example:
A = "1998-04-18 16:48:36.76,0,38"
B = "1998-04-18 16:48:37,5,33"
# Note the difference ^^
# Output for B:
['1998-04-18 16:48:37', '5', '33']
stDate before: 1998-04-18 16:48:37
stDate after: 1998-04-18 16:48:37.4
dat_time: 1998-04-18 16:48:37.400000
mic_sec: 400000
timecon: 892918117400000
strDate: "1998-04-18 16:48:37.4"
# Output for A:
['1998-04-18 16:48:36.76', '0', '38']
stDate before: 1998-04-18 16:48:36.76
dat_time: 1998-04-18 16:48:36.760000
mic_sec: 760000
timecon: 892918116760000
strDate: "1998-04-18 16:48:36.76"
将所有内容都集成到您的主循环中。这是您总体上想要的：
对于k，
Integrated Everything into your main loop. This is what you want overall:
for k, line in enumerate(lines):
if k > (int(header_line)):
data_pre = line.strip().split(',')
stDate = data_pre[0].replace("\"", "")
print stDate
try:
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
except:
stDate = stDate + ".4"
dat_time = datetime.datetime.strptime(stDate,
'%Y-%m-%d %H:%M:%S.%f')
mic_sec = dat_time.microsecond
timcon = calendar.timegm(dat_time.timetuple())*1000000 + mic_sec
strDate = "\"" + stDate + "\""
# ^ Changed this line
print strDate
# ^ Changed this line
原始最终答案：
您不能附加到字符串。
Original Answer:
You can't append to a string.
一种选择是使用 A + B
A = "1998-04-18 16:48:36"
B = ".0"
C = A + B
C = "1998-04-18 16:48:36.0"
您还可以使用 str.join ：
D = "".join([A,B])
D = '1998-04-18 16:48:36.0'
有关更多信息，请参见以下问题的答案：在Python中连接字符串的首选方法是什么？
For more info, see the answer to this question: Which is the preferred way to concatenate a string in Python?
这篇关于ValueError：时间数据与格式'％Y-％m-％d％H：％M：％S.％f'不匹配的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！
