在字符串数组中查找下一个可用的日期 [英] Find next available day in an Array of string
问题描述
我一直在尝试根据当前日来计算下一个可用的日期,即如果今天是星期五,则在Array中搜索下一个最近的日期,例如Array的值是1 [Monday],2 [Tuesday ],4 [星期四],6 [星期六],那么我的第二天应该是星期六。
I've been trying to figure out how to take next available day based on Present day i.e., if today is Friday, then search in Array for the next nearest day like if Array values are 1[Monday], 2[Tuesday], 4[Thursday], 6[Saturday] then my next day should be Saturday.
这是我尝试过的
//Here i'll get days like 0, 2, 3, 4, 6 pattern, and i'm spliting them based on comma to get single-single day value in array of string
string[] GetDays = DayInWeek.Split(','); [Here day patterns will change everytime, based on user selection]
//Here i'm looping to take each day and get Enum Text based on Enum Value
foreach (string FirstDay in GetDays)
{
//Here i'm converting the string value into int and passing to DayOfWeek Enum to get respective day
DayOfWeek DayChoosen = ((DayOfWeek)(Convert.ToInt32(FirstDay)));
//Here i have my actual day for example Friday
DayOfWeek StartDay = "Friday";
//Here i need condition to find next available day in the foreach i.e., after Friday next value should be Saturday, or Sunday, Monday & so on until Friday==Friday
if (StartDay == DayChoosen)
{
//End foreach
}
}
我根据当日告诉我,我应该找到下一个可用的日子,即如果星期五我应该搜索星期六,如果星期六不在那儿,那么星期日,星期一等,直到星期五=星期五
As i told based on present Day i should find next available day i.e, if Friday i should search for Saturday, if Saturday is not there then Sunday, Monday and so on till Friday=Friday
推荐答案
您不需要使用 foreach进行所有这些操作
。
您可以执行以下操作:
private int nextDay(string dayInWeek, int startDay)
{
int[] getDays = dayInWeek.Split(',').Select(int.Parse).ToArray();
return getDays.Where(d => d > startDay).Any()
? getDays.Where(d => d > startDay).Min()
: getDays.Min();
}
此算法检查一周中是否有某些天显示在您的数组,然后放在 startDay
之后。否则,它将输出一周中的第一天。
This algorithm checks if there are any days of a week, which are presented in your array, and come after the startDay
. Else, it outputs the first available day in a week.
例如,对于字符串 0、2、3、4、6:
For example, for a string "0, 2, 3, 4, 6":
- for
startDay
0-输出2,因为它是大于0的最小整数 - for
startDay
1-输出2 - for
startDay
3-输出4 - 对于
startDay
6,它没有找到大于6的项目,并且输出最少0
- for
startDay
0 - output 2, as it is the minimal integer which is more than 0 - for
startDay
1 - outputs 2 - for
startDay
3 - output 4 - for
startDay
6 it finds no items, which are more than 6, and outputs minimum 0
对于字符串 5(仅周五):
For string "5" (Friday only):
- for
startDay
5,6-没有发现超过5的项目,输出最小值(5) -
startDay
0-4-输出5,作为大于0-4的最小数字
- for
startDay
5, 6 - finds no items which are more than 5, output minimum (5) - for
startDay
0-4 - outputs 5, as the minimum number which is greater than 0-4
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