在SQL Server中合并重叠的日期 [英] Merge overlapping dates in SQL Server

问题描述

我有一个包含3列的表：

I have a table that contains 3 columns :

Name |  Datetime_Start  | Datetime_End
 A   | 2017-01-02 00:00 | 2017-03-28 00:10
 A   | 2017-05-14 23:50 | 2017-05-29 23:50
 B   | 2017-05-18 00:00 | 2017-05-18 04:00
 B   | 2017-05-18 02:00 | 2017-05-18 03:00
 C   | 2017-01-02 00:00 | 2017-01-17 15:50
 C   | 2017-01-14 03:50 | 2017-01-28 15:50

我希望输出像这样，（基本上合并

I would like the output to be like this,(basically merge overlapping periods into one):

Name |  Datetime_Start  | Datetime_End
 A   | 2017-01-02 00:00 | 2017-03-28 00:10
 A   | 2017-05-14 23:50 | 2017-05-29 23:50
 B   | 2017-05-18 00:00 | 2017-05-18 04:00
 C   | 2017-01-02 00:00 | 2017-01-28 15:50

我尝试使用此处的建议：消除并减少重叠的日期范围

I tried to use what's suggested here : Eliminate and reduce overlapping date ranges

但是我的结果未正确合并，我认为这是由于我的datetime值的时间部分所致。

But my results are not merged correctly and I think it's due to the time part of my datetime values...

如果一个期间在另一个准确的时刻结束，则应合并句点。

If a period ends at the exact moment the other one starts, the periods should be merged.

select Name, Min(NewStartDate) Datetime_Start, MAX(Datetime_End) Datetime_End
from
(
    select *,
        NewStartDate = t.Datetime_Start+n.number,
        NewStartDateGroup =
            dateadd(d,
                    1- DENSE_RANK() over (partition by Name order by t.Datetime_Start+n.number),
                    t.Datetime_Start+n.number)
    from Mytable t
    inner join dbo.Numbers n
      on n.number <= DATEDIFF(d, Datetime_Start, Datetime_End)
) X
group by Name, NewStartDateGroup

（dbo.Numbers包含1列从0到1000000的数值）

(dbo.Numbers contains 1 column of number values from 0 to 1 000 000)

输出：

   Name     | Datetime_Start            | Datetime_End
 A          | 2017-11-04 00:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-04 23:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-05 00:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-05 23:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-06 23:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-07 00:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-07 23:10:00.000   | 2017-12-05 15:10:00.000
 A          | 2017-11-08 00:10:00.000   | 2017-12-05 15:10:00.000

推荐答案

SQL DEMO

SQL DEMO

declare @t table (Name varchar(100),  Datetime_Start  datetime,  Datetime_End datetime);
insert into @t values
 ('A'   , '2017-01-02 00:00' , '2017-03-28 00:10'),
 ('A'   , '2017-05-14 23:50' , '2017-05-29 23:50'),
 ('B'   , '2017-05-18 00:00' , '2017-05-18 04:00'),
 ('B'   , '2017-05-18 02:00' , '2017-05-18 03:00'),
 ('C'   , '2017-01-02 00:00' , '2017-01-17 15:50'),
 ('C'   , '2017-01-14 03:50' , '2017-01-28 15:50');

with Datetime_Starts as 
( 
  select distinct name, Datetime_Start 
  from @t as t1 
  where not exists 
    (select * from @t as t2 
     where t2.name = t1.name 
       and t2.Datetime_Start < t1.Datetime_Start 
       and t2.Datetime_End >= t1.Datetime_Start) 
), 
Datetime_Ends as 
( 
  select distinct name, Datetime_End 
  from @t as t1 
  where not exists 
    (select * from @t as t2 
     where t2.name = t1.name 
       and t2.Datetime_End > t1.Datetime_End 
       and t2.Datetime_Start <= t1.Datetime_End) 
) 

select name, Datetime_Start, 
      (select min(Datetime_End) 
        from Datetime_Ends as e 
        where e.name = s.name 
            and Datetime_End >= Datetime_Start) as Datetime_End 
    from Datetime_Starts as s;

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