计算不同时区中日期之间的小时数 [英] Calculate hours between dates in different time zones

问题描述

我有一组日期（在格林威治标准时间的不同时区），我想计算第一个日期和最后一个日期之间经过的小时数。

例如，这将是一个日期数组：

  [
 1 => ; 2016-06-05T08：45：00.000 + 02：00，
 2 => 2016-06-05T09：55：00.000 + 02：00，
 3 => 2016-06-05T12：10：00.000 + 02：00，
 4 => 2016-06-05T14：25：00.000-04：00 
] 
  

我想计算从索引1到2、2到3以及从3到4的日期以来经过的小时数。问题是我不知道如何根据时区进行计算，如果我必须加或减小时才能得到正确的结果。

我需要知道如何开发代码。可能会是这样（因为缺少根据时区进行计算）：

  $ tIda = 0; 
 
 foreach（$ times0 as $ i => $ time）
 {
 if（$ i< sizeof（$ times0）-1）
 {
 $ datetime1 = strtotime（substr（$ time，0，10）。''。substr（$ time，11，8））; 
 $ datetime2 = strtotime（substr（$ times0 [$ i + 1]，0，10）。’’substr（$ times0 [$ i + 1]，11，8））; 
 $ interval = abs（$ datetime2-$ datetime1）; 
 $ tIda + = round（$ interval / 60）; 
} 
} 
  

谢谢。

解决方案

最好的解决方案是使用 DateTime 类。

首先，根据日期字符串创建 \DateTime 对象：

  $ datetime1 = new \DateTime（$ time）; 
 $ datetime2 = new \DateTime（$ times0 [$ i + 1]）; 
  

然后，您可以使用 diff（）

计算两个日期之间的时差。 code>方法：

  $ diff = $ datetime1-> diff（$ datetime2）; 
  

$ diff 是<$的实例c $ c> \DateTimeInterval ，您可以按自己喜欢的方式设置此差异的格式，例如：

  $ diff-> format（'％H：％I：％S'）
  

I have an array of dates (in different time zones GMT) and I would like to calculate the hours that have elapsed between the first and the last date.

For example, this would be an array of dates:

[
    1 => 2016-06-05T08:45:00.000+02:00,
    2 => 2016-06-05T09:55:00.000+02:00,
    3 => 2016-06-05T12:10:00.000+02:00,
    4 => 2016-06-05T14:25:00.000-04:00
]

I want to calculate the hours that have elapsed since the date with index 1 to 2, 2 to 3 and from 3 to 4. The problem is I do not know how to calculate according to the time zone, if I must add or subtract hours to get the right result.

I need to know how it is calculated to develop the code. It would be something (for lack of calculated according to the time zone):

$tIda = 0;

foreach ($times0 as $i => $time)
{
    if ($i < sizeof($times0) - 1)
    {
        $datetime1 = strtotime(substr($time, 0, 10) . ' ' . substr($time, 11, 8));
        $datetime2 = strtotime(substr($times0[$i + 1], 0, 10) . ' ' . substr($times0[$i + 1], 11, 8));
        $interval  = abs($datetime2 - $datetime1);
        $tIda += round($interval / 60);
    }
}

Thanks.

解决方案

The best solution would be to use DateTime classes.

First, you create \DateTime objects from date strings:

$datetime1 = new \DateTime($time);
$datetime2 = new \DateTime($times0[$i + 1]);

Then you can calculate the difference between two dates using diff() method:

$diff = $datetime1->diff($datetime2);

$diff is an instance of \DateTimeInterval, and you can format this difference any way you like, for example:

$diff->format('%H:%I:%S')

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