如何形成引用多个资源的SPARQL查询 [英] How to form SPARQL queries that refers to multiple resources

问题描述

我的问题是对我的跟进关于SPARQL的第一个问题在这里。

我对Mountain对象的SPARQL查询结果是此处。

My SPARQL query results for Mountain objects are here.

从这些结果中，我选择了一个对象资源。
现在，我要为此选定的Mountain对象获取 是dbpedia-owl：highestPlace of 记录的值。

From those results I picked a certain object resource. Now I want to get values of "is dbpedia-owl:highestPlace of" records for this chosen Mountain object.

即，此山最高的山脉的名称。

That is, names of mountain ranges for which this mountain is highest place of.

我认为这很复杂。不仅因为我不知道所需的语法，而且在这里我得到了两个对象。

This is, as I figure, complex. Not only because I do not know the required syntax, but also I get two objects here.

• 其中一个是类型为地方的Mont Blank Massif 。


• 另一个是西阿尔卑斯山，其类型为山峰范围-我想要的记录。

• One of them is Mont Blank Massif which is of type "place".
• Another one is Western Alps which is of type "mountain range" - my desired record.

我需要上面的记录＃2，但不需要1。我知道1也很重要，但有时它并没有不遵循相同的模式。有时记录似乎是YAGO类型的记录，这可能完全令人误解。为了安全起见，我只想在类型不匹配时就丢弃这些记录。

I need record # 2 above but not 1. I know 1 is also relevant but sometimes it doesn't follow same pattern. Sometimes the records appear to be of YAGO type, which can be totally misleading. To be safe, I simply want to discard those records whenever there is type mismatch.

如何形成我的SPARQL查询以获取这些 是dbpedia-owl ：记录的最高位置，并且还具有类型过滤功能？

How can I form my SPARQL query to get these "is dbpedia-owl:highestPlace of" records and also have the type filtering?

推荐答案

您可以使用此查询，但是请注意，在您的示例中， Mont_Blanc_massif 都是 dbpedia-owl：Place 和 dbpedia-owl：MountainRange

you can use this query, note however that Mont_Blanc_massif in your example is both a dbpedia-owl:Place and a dbpedia-owl:MountainRange

select * where {
   ?place dbpedia-owl:highestPlace :Mont_Blanc.
   ?place rdf:type dbpedia-owl:MountainRange.
}

运行查询

评论后编辑：过滤器

不清楚要过滤的内容（是吗？），从技术上讲，您可以像这样进行过滤：

edit after comment: filter
It is not really clear what you want to filter (yago?), technically you can filter for example like this:

select * where {
   ?place dbpedia-owl:highestPlace :Mont_Blanc.
   ?place rdf:type dbpedia-owl:MountainRange.
   FILTER NOT EXISTS { 
     ?place ?pred ?obj
     Filter (regex(?obj, "yago"))
   }
}

这会过滤出结果中包含任何 object 中带有 yago的结果网址。

this filters out results that have any object with 'yago' in its URL.

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