从十进制删除尾随零 [英] drop trailing zeros from decimal

问题描述

我有一长串的十进制数，我必须根据某些条件将其调整为10、100、1000，.... 1000000。当我将它们相乘时，有时会想要删除一个无用的尾随零（尽管并非总是如此）。例如...

I have a long list of Decimals and that I have to adjust by factors of 10, 100, 1000,..... 1000000 depending on certain conditions. When I multiply them there is sometimes a useless trailing zero (though not always) that I want to get rid of. For example...

from decimal import Decimal

# outputs 25.0,  PROBLEM!  I would like it to output 25
print Decimal('2.5') * 10

# outputs 2567.8000, PROBLEM!  I would like it to output 2567.8
print Decimal('2.5678') * 1000

是是否有一个函数告诉小数对象舍弃这些无关紧要的零？我能想到的唯一方法是转换为字符串并使用正则表达式替换它们。

Is there a function that tells the decimal object to drop these insignificant zeros? The only way I can think of doing this is to convert to a string and replace them using regular expressions.

应该提到我正在使用python 2.6.5

Should probably mention that I am using python 2.6.5

编辑
senderle的好答案使我意识到，我偶尔会得到一个像250.0这样的数字，当归一化时会产生2.5E + 2。我猜在这些情况下，我可以尝试将它们整理出来并转换为int

EDIT senderle's fine answer made me realize that I occasionally get a number like 250.0 which when normalized produces 2.5E+2. I guess in these cases I could try to sort them out and convert to a int

推荐答案

可能有更好的方法，但您可以使用 .rstrip（'0'）。rstrip（'。'）来获得所需的结果。

There's probably a better way of doing this, but you could use .rstrip('0').rstrip('.') to achieve the result that you want.

以您的数字为例：

>>> s = str(Decimal('2.5') * 10)
>>> print s.rstrip('0').rstrip('.') if '.' in s else s
25
>>> s = str(Decimal('2.5678') * 1000)
>>> print s.rstrip('0').rstrip('.') if '.' in s else s
2567.8

这是杰里特在评论中指出的问题的解决方法：

And here's the fix for the problem that gerrit pointed out in the comments:

>>> s = str(Decimal('1500'))
>>> print s.rstrip('0').rstrip('.') if '.' in s else s
1500

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