从十进制数字中删除小数点 [英] Remove decimal point from a decimal number

问题描述

我正在尝试从C＃中的十进制数字中删除小数点。

例如：

• 我的十进制数字是 2353.61 我想要的结果是 235361 。


• 我的十进制数字是 196.06 我想要的结果是 19606 。

我该怎么做？

解决方案

我将简单地获取小数位数并乘以10的正确乘方数。可能不是真正的问题，但这也将更快，使用更少的内存，然后将其转换为字符串拆分/重组，然后将其转换回a双。

  decimal d = 2353.61M; 
 int count = BitConverter.GetBytes（decimal.GetBits（d）[3]）[2]; 
 d * = Convert.ToDecimal（Math.Pow（10，count））; 
  

使用
小数位数

I am trying to remove just the decimal point from a decimal number in C#.

For example:

• My decimal number is 2353.61 I want 235361 as the result.
• My decimal number is 196.06 I want 19606 as the result.

How can I do that?

解决方案

I would simply get the number of decimals and multiply it by the correct power of 10. Probably not really a concern but this also would be faster and use less memory then casting it to a string splitting / recombining it, then casting it back to a double. This also works for any number of decimal places.

decimal d = 2353.61M;
int count = BitConverter.GetBytes(decimal.GetBits(d)[3])[2];
d *= Convert.ToDecimal(Math.Pow(10, count));

Using this answer to get the number of decimals.

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