怎么把十六进制转换成十进制？ [英] How to convert Hexadecimal to Decimal?

问题描述

我要传入不同的十六进制数据并将其存储到整数类型寄存器中。

I have different hexadecimal data are coming and stored into an integer type register.

当我使用fprint时，我可以看到以下内容：

When I use fprint I can see the following:

0x3076
0x307c
.
.
.

不过，我想显示上述十六进制数据的十进制版本。

However, I would like to show a Decimal version of above-mention Hex data as follows.

12406
12412
.
.
.

从理论上讲，对于第一个值，您可以执行以下操作将其转换为十进制。

In theory, let's say for the first value you do the following to convert it to decimal.

(6* 16^0)+(7 * 16^1)+(0*16^2)+(3*16^3)=6 + 112+ 0 + 12288 = 12406

所以如果我有基于字符的版本 0x3076，并且，如果我能够获得每个字符6-7-0-3，我可以计算小数位数！

So IF I have the character-based version of "0x3076" and also, IF I am able to get each single characters 6 - 7 - 0 - 3, I can calculate the decimal amount!

所以，我决定将 3076除以1000。我应该得到3，但是我得到了两个字符！但是，如果我能在 307c的其余部分中获得3，则不能获得 C。如果是十进制，则可能无法使用十六进制！

So, I decided to divide "3076" by 1000. I was expected to get 3, but I got TWO characters instead! however, if I was able to get 3 for the remainder of "307c" I am not able to get "C". If it was decimal this might work not hex!

此外，我尝试了 strtol 命令。当我使用Cygwin编译代码时，我不确定错误在哪里！我做错了什么？

Also, I tried "strtol" command. As I use Cygwin to compile my code, I am not sure where the error is! What did I do wrong?

因此，我只需要找到一种方法即可从十六进制数据中获取每个单字符！

So, I just need to find a way to get EACH SINGLE character out of the HEX data!

有什么想法吗？

PS

这是我的代码，可以帮助您

Here is my code in order to help you to give me an idea.

   int get_readings(int source, int phase, int max_tries)
{
    uint8_t buf[MAX_IEC1107_MSG_BODY];
    uint8_t inbuf[MAX_IEC1107_MSG_BODY];
    int inlen;
    uint8_t *s;
    int32_t value;
    int status;
    double voltage;
    double current;
    double active_power;
    double reactive_power;
    double apparent_power;
    double power_factor;
    double frequency;

    s = buf;
    *s++ = HOST_CMD_GET_READINGS_PHASE_1 + phase;
    *s++ = 0x00;
    if (max_tries != 1)
        meter_set_max_tries(&emeter[source].meter_msg, max_tries);
    if (meter_exchange(&emeter[source].meter_msg, buf, 2, inbuf, &inlen)
        &&
        inbuf[1] != 0xFF)
    {
        emeter[source].no_response = FALSE;
        s = inbuf;
        /* Get current readings */
        value = (s[3] << 8) | s[2];

        fprint(stderr, "value:" %p\n, value); // this give me HEX code

。
。
。

. . .

推荐答案

只有使用以下行，我才能解决问题！

Only with the following line I could solve the issue!

fprintf(stderr, "Voltage: %.2f\n", value/100.00);

值显示为十六进制，因为我以前使用％p！然后我换成了x！因为我需要124.06而不是12406，换句话说，是2个小数点，所以我加了.2f！

value was shown as HEX as I used to use %p! Then I changed to x! and as I need to have 124.06 not 12406, in other words 2 decimal points, I added .2f!

谢谢大家！

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