R错误：“在数值表达式中有19个元素：只有第一个使用”。 [英] R Error: "In numerical expression has 19 elements: only the first used"

问题描述

我创建了一个数据框：

totalDeposit <- cumsum(testd$TermDepositAMT[s1$ix])

基本上是计算被测试数据帧中TermDeposit金额的累积总和并将其存储在总存款中。

which is basically calculating cumulative sum of TermDeposit amounts in testd dataframe and storing it in total deposit. This works perfrectly ok.

然后我需要计算存款金额的平均值，然后使用以下内容：

I then need to calculate the average of the deposit amount and i use the following:

avgDeposit <- totalDeposit / (1:testd)

但收到错误消息

   Error in 1:testd : NA/NaN argument
In addition: Warning message:
In 1:testd : numerical expression has 19 elements: only the first used

tested具有大约8000个观测值和19个变量。

testd has some 8000 observations and 19 variables.

有人可以帮我解决这个问题吗？我试图在线查找此错误消息，但到目前为止，我所了解的只是：1：tested基本上使R读取了testd作为不是的数字，因此我得到了一条错误消息。会简单地采取mean（totalDeposit）的技巧吗？我尝试过，但是我得到的数字是荒谬的，无处代表平均值。

Could someone help me get past this issue? I've attempted to locate this error message online but all i've understood so far is that 1:testd basically makes R read testd as a number which it isn't and hence i get an error message. Would simply taking mean(totalDeposit) do the trick? I tried it but the figure i get is absurd and nowhere representative of the average.

谢谢您的帮助。

推荐答案

在这种情况下，错误消息很有帮助。

The error message is, in this case, helpful.

当您说 1时： N ，您告诉R是给我1到N之间的整数序列。从整数1到整数2。 testd 不是整数，（最好）是整数的整个向量，因此R会处理除 testd <中的第一个值以外的所有值。 / code>计算序列时。替代方案可能是可怕的错误，也可能是序列的 set -一个介于1和 testd 中的第一个值之间，另一个介于1和第二个之间 tested ...中的值，依此类推。

When you say 1:N, what you're telling R is "give me the sequence of integers between 1 and N". It's from integer1 to integer2. testd isn't an integer, it's (at best) an entire vector of integers, and so R disposes of all but the first value in testd when calculating the sequence. The alternative would be either a horrible error or a set of sequences - one between 1 and the first value in testd, another between 1 and the second value in testd...and so on.

您想要的是 1 ：nrow（testd），如果testd是数据帧，并且 1：length（testd）或 seq_along（已测试）是列表还是向量。

What you want instead is 1:nrow(testd), if testd is a data frame, and either 1:length(testd) or seq_along(testd) if it's a list or vector.

不过，根据问题-是否需要计算平均值？ -您实际上正在解决这个错误，因为您不想要一个值序列，而只想要一个：由于average =总数/进入该总数的元素数量，您只需要'元素数量'-可以使用 nrow（tested）进行检索。

Based on the question, though - the need to calculate averages? - you're actually approaching this wrong, because you don't want a sequence of values, you just want one: since average = total/number of elements that went into that total, you just want 'the number of elements' - which can be retrieved simply with nrow(testd).

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