在Python中为每个实例装饰方法 [英] Decorate methods per instance in Python
问题描述
假设我有一些简单的课程
Assume I have some simple class
class TestClass:
def doSomething(self):
print 'Did something'
我想装饰 doSomething
方法,例如计算呼叫次数
I would like to decorate the doSomething
method, for example to count the number of calls
class SimpleDecorator(object):
def __init__(self,func):
self.func=func
self.count=0
def __get__(self,obj,objtype=None):
return MethodType(self,obj,objtype)
def __call__(self,*args,**kwargs):
self.count+=1
return self.func(*args,**kwargs)
现在,这计算了对装饰方法的调用次数,但是我希望每个实例都有一个计数器,例如
Now this counts the number of calls to the decorated method, however I would like to have per-instance counter, such that after
foo1=TestClass()
foo1.doSomething()
foo2=TestClass()
foo1.doSomething.count
为1和 foo2.doSomething.count
为0。据我了解,使用装饰器是不可能的。有什么方法可以实现这种行为?
foo1.doSomething.count
is 1 and foo2.doSomething.count
is 0. From what I understand, this is not possible using decorators. Is there some way to achieve such behaviour?
推荐答案
利用自己$ c $的事实c>(即调用该方法的对象)作为参数传递给该方法:
Utilize the fact that self
(i.e. the object which the method is invoked on) is passed as a parameter to the method:
import functools
def counted(method):
@functools.wraps(method)
def wrapped(obj, *args, **kwargs):
if hasattr(obj, 'count'):
obj.count += 1
else:
obj.count = 1
return method(obj, *args, **kwargs)
return wrapped
在上面的代码中,我们将对象拦截为 obj
方法的修饰版本的参数。装饰器的用法非常简单:
In above code, we intercept the object as obj
parameter of the decorated version of method. Usage of the decorator is pretty straightforward:
class Foo(object):
@counted
def do_something(self): pass
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