将ereg_replace转换为preg_replace [英] Converting an ereg_replace to preg_replace

问题描述

我必须将 ereg_replace 转换为 preg_replace

ereg_replace代码为：

The ereg_replace code is:

ereg_replace( '\$([0-9])', '$\1', $value );

preg由开始和结束反斜杠表示，我认为转换是：

As preg is denoted by a start and end backslash I assume the conversion is:

preg_replace( '\\$([0-9])\', '$\1', $value );

由于我对正则表达式没有很好的了解，所以我不确定以上是否是

As I don't have a good knowledge of regex I'm not sure if the above is the correct method to use?

推荐答案

ereg_replace（）和 preg_replace（）是该模式必须用定界符括起来：定界符+模式+定界符。如文档所述，分隔符可以是任何非分隔符。 -字母数字，非反斜杠，非空格字符。这意味着有效的定界符为： / ，＃，〜， + ，％， @ ，！和<> ，其中前两个最常用（但这只是我的猜测）。

One of the differences between ereg_replace() and preg_replace() is that the pattern must be enclosed by delimiters: delimiter + pattern + delimiter. As stated in the documentation, a delimiter can be any non-alphanumeric, non-backslash, non-whitespace character. This means that valid delimiters are: /, #, ~, +, %, @, ! and <>, with the first two being most often used (but this is just my guess).

如果您的 ereg_replace（）可以按预期工作，则只需在模式中添加定界符即可。以下所有示例均适用：

If your ereg_replace() worked as you expected, then simply add delimiters to the pattern and it will do the thing. All examples below will work:

preg_replace('/\$([0-9])/', '$\1', $value);

或

preg_replace('#\$([0-9])#', '$\1', $value);

或

preg_replace('%\$([0-9])%', '$\1', $value);

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