调用基类静态方法时获取Caller派生类 [英] Get Caller derived-class when calling a base-class static method

问题描述

我想知道是否有可能（甚至通过反射等）将调用者的派生类获取到称为基类的静态方法中。

I was wondering if it's possible (even via reflection et similia) to get the caller derived-class inside of a called base-class static method.

，我有一个定义了静态方法的基类：

For example, I've a base-class with a static method defined:

public MyBaseClass {
    public static void MyBaseClassStaticMethod() { /** ... **/ }
}

以及派生的- from-it类：

and a derived-from-it class:

public MyDerivedClass : MyBaseClass { }

然后我打电话：

MyDerivedClass.MyBaseClassStaticMethod()

是否可以在方法 MyBaseClassStaticMethod 内使用是呼叫者派生类型？

（即 MyDerivedClass ）

Is it possibile, inside of method MyBaseClassStaticMethod, to know which is the caller derived type?
(i.e. MyDerivedClass)

我只需要一个字符串...

I just need a string...

推荐答案

不，这是不可能的-绝不是。 静态方法不是多态的，因此这些信息根本不存在。

考虑重新设计代码。

No, this is not possible - by no means. static methods are not polymorphal and as such this information simply doesn't exist.
Consider redesigning your code.

更新：

编译后，编译器将 MyDerivedClass 替换为静态方法是实际上在您的情况下声明为 MyBaseClass 。

因此，即使在IL中，您也看不到 MyDerivedClass 。该信息在源代码中仅存在 。它在您的已编译程序集中不存在。

Upon compilation, the compiler replaces MyDerivedClass with the class the static method is actually declared on, in your case MyBaseClass.
So even in the IL you don't see MyDerivedClass. The information exists only in your source code. It doesn't exist in your compiled assembly.

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