RestSharp将空字符串反序列化为字典错误 [英] RestSharp Deserialization of empty string to Dictionary Error

问题描述

我对RestSharp有点陌生，所以请原谅我的无知。我收到以下错误：

I'm a bit new to RestSharp so please excuse my ignorance. I'm getting the following error:

 {"Unable to cast object of type 'System.String' to type 'System.Collections.Generic.IDictionary`2[System.String,System.Object]'."}

此当RestSharp尝试反序列化并将空字符串转换为Dictionary对象时发生。

This happens when RestSharp tries to deserialize and empty string to a Dictionary object.

这是我缩写的Result对象：

Here is the my abbreviated Result object:

public class Result
{
     public Dictionary<string, string> assignment_group { get; set; }
}

如果填充了assignment_group，则返回以下内容：

Here is what is returned if assignment_group is populated:

"assignment_group":{"link":"https://someurl/api/now/table/sys_user_group/2c1cf1176f29f5007a3db03f5d3ee4aa","value":"2c1cf1176f29f5007a3db03f5d3ee4aa"}

如果未填充assignment_group，则返回以下内容：

Here is what is returned if assignment_group is not populated:

"assignment_group":""

正在发生的事情是，assignment_group的JSON响应将是字典或空字符串。如果是空字符串，我只会收到错误消息。如何在Result类的Assignment_group属性中容纳两种返回类型？

What is happening is the JSON response for assignment_group will be a Dictionary or an empty string. I will only get the error if it's an empty string. How can I accommodate both return types in my Result class assignment_group property?

在此先感谢您的帮助。

更新：
这是对我有用的解决方案。

Update: Here is working solution for me.

我使用的是Newtonsoft，而不是RestSharp使用的默认反序列化器。杰森代替。这是来自我的包装器类的代码示例：

Instead of default Deserializer used by RestSharp, I used Newtonsoft.Json instead. Here is code example from my wrapper class:

 public T Execute<T>(RestRequest request) where T : new()
 {
        if (request.Method == Method.POST)
            client.FollowRedirects = false;

        var response = client.Execute<T>(request);

        // **** Added Newtonsoft.Json ****
        var x = JsonConvert.DeserializeObject<T>(response.Content);


        LogRequest(request, client);
        LogResponse<T>(response);

        ErrorHandling<T>(response);

       //  ****This is no longer needed. Data is null now****
       // return response.Data;  

       //  **** Added **** 
       return x;
 }

推荐答案

您是否正在使用为此自定义序列化器/反序列化器？因为我的理解是涵盖了以下情况（但您的示例未涉及）：

Are you making use of a custom serializer/deserializer for this? Because my understanding is that the following cases are covered (but your example is not):

1. assignment_group = null;
   结果为 assignment_group：空


2. assignment_group = new Dictionary（）;
   结果为 assignment_group： {}


3. assignment_group = new Dictionary（）; assignment_group.Add（ key， value）;
   结果为 assignment_group： {键：值}

这也可能与以下内容有关： https://github.com/restsharp/RestSharp/issues/486

This may also be related to: https://github.com/restsharp/RestSharp/issues/486

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