递归地遍历带有列表的嵌套字典,并替换匹配的值 [英] Recursively iterate through a nested dict with list, and replace matched values
问题描述
我想做一个通过包含列表的嵌套字典迭代的函数。对于每个与关键字匹配的值,该函数将其替换为另一个关键字。
该函数返回另一个dict或更改主dict并不重要。 / p>
我试图将情况分开:
-如果数据是字典,则进行某些操作
-如果数据是列表,则进行其他操作
DICT:
data_dict = {
name: AAAAAA,
content: BBBBBB,
dat:[
{
author :{{
name: CCCCCC,
surname: DDDDDD,
},
title: FFFFFF,
color :15258703,
字段:[
{
name: GGGGGG,
value: HHHHHH,
},
{
name: IIIIII,
value: JJJJJJ,
}
],
缩略图: {
url: KKKKKK
},
image:{
url: LLLLLL
},
footer:{
text: MMMMMMM,
icon_url : NNNNNN
}
}
]
}
现在我只是想更改每个值以查看是否也要进行迭代。
我可以打印所有更改后的 data_dict
,但是我无法在字典中对其进行管理...
def recursive_replace_valuer(data,match,repl):
如果isinstance(data,list) :数据中的l的
:
recursive_replace_valuer(l,match,repl)
if isinstance(l,dict):
recursive_replace_valuer(l,match,repl)
elif isinstance(data,dict):
for data中的k,v.items():
recursive_replace_valuer(v,match,repl )
data [k] ='______'
print(data)
recursive_replace_valuer(data_dict,'a','a')
该函数应递归地将该函数应用于字典或列表中的值,直到输入 data
既不是字典也不是列表,这时如果替换值 repl
,则返回替换值给定的数据与给定的搜索字符串 match
:
def replace(数据,匹配项,替换项):
如果isinstance(数据,字典):
返回{k:data.items()中k,v的replace(v,match,repl)}
elif isinstance(data,list):
返回[在数据中为i替换(i,match,repl)]
else:
如果data ==匹配else data
返回repl
或者就地替换原始数据,使函数遍历给定的dict或list并替换为键(用于dict)或索引(用于列表)(如果匹配),然后将该函数递归应用到值:
def replace(数据,匹配,替换):
如果isinstance(数据,(字典,列表)):
对于k,v in(data.items()如果isinstance(数据,字典)否则枚举(数据)):如果v ==匹配,则为
:
data [k] = repl
replace(v,match,repl)
I want to make a function that iterate through a nested dict that include list. For each value that match with a keyword, the function replace it with another keyword.
It's not important if the function return another dict or if it change the main dict.
I tried to separate the case: - if the data is a dict, make something - if the data is a list, make something else
DICT:
data_dict = {
"name": "AAAAAA",
"content": "BBBBBB",
"dat": [
{
"author": {
"name": "CCCCCC",
"surname": "DDDDDD",
},
"title": "FFFFFF",
"color": 15258703,
"fields": [
{
"name": "GGGGGG",
"value": "HHHHHH",
},
{
"name": "IIIIII",
"value": "JJJJJJ",
}
],
"thumbnail": {
"url": "KKKKKK"
},
"image": {
"url": "LLLLLL"
},
"footer": {
"text": "MMMMMMM",
"icon_url": "NNNNNN"
}
}
]
}
Now I'm just trying to change each value to see if I'm iterate as well.
I can print all the data_dict
with value changed, but I can't manage it in a dict...
def recursive_replace_valuer(data, match, repl):
if isinstance(data, list):
for l in data:
recursive_replace_valuer(l, match, repl)
if isinstance(l, dict):
recursive_replace_valuer(l, match, repl)
elif isinstance(data, dict):
for k,v in data.items():
recursive_replace_valuer(v, match, repl)
data[k] = '______'
print(data)
recursive_replace_valuer(data_dict, 'a','a')
The function should recursively apply the function to the values in a dict or a list until the input data
is neither a dict nor a list, at which point return the replacement value repl
if the given data matches the given search string match
:
def replace(data, match, repl):
if isinstance(data, dict):
return {k: replace(v, match, repl) for k, v in data.items()}
elif isinstance(data, list):
return [replace(i, match, repl) for i in data]
else:
return repl if data == match else data
Or to replace the original data in-place, make the function iterate through the given dict or list and replace a value by the key (for dict) or index (for list) if it's a match, and recursively apply the function to the value:
def replace(data, match, repl):
if isinstance(data, (dict, list)):
for k, v in (data.items() if isinstance(data, dict) else enumerate(data)):
if v == match:
data[k] = repl
replace(v, match, repl)
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