以任意顺序对键进行排序 [英] sort keys in arbitrary order

问题描述

对于副项目，我想使用jq对JSON的键进行排序，并提出以下解决方案：

For a side-project I want to sort the keys of a JSON with jq, and come up with the following solution:

def add_property_prefix:
    if .key == "beka" then "01__"+.key
    elif .key == "alma" then "02__"+.key
    elif .key == "paprika" then "03__"+.key
    elif .key == "korte" then "04__"+.key
    else .key end
;

def del_property_prefix:
    .key | sub("^[0-9]{2}__"; "")
;

to_entries
| map({ key: add_property_prefix, value: .value })
| sort_by(.key)
| map({ key: del_property_prefix, value: .value })
| from_entries

输入的JSON如下所示：

And the input JSON looks like this:

{
    "alma": 1,
    "beka": 2,
    "paprika": 3,
    "korte": 4
}

（ jq play lin k ）

虽然可行，但我有10个以上的键，并且 add_property_prefix 函数确实很有效

While this works, I have more than 10 keys and the add_property_prefix function is really bloaty because of this.

问题：是否有办法减少排序列表的冗余度？

我在想某种地图，但我不太了解jq以找出更优雅的解决方案。

I was thinking of some kind of map, but I don't know jq that much to figure out a more elegant solution.

推荐答案

指定键及其顺序：

 { beka, alma, paprika, korte }

Caveat

仅适用于带有普通名称。例如，由于 end 是jq关键字，因此您必须编写：

Caveat

This only works for keys with "ordinary" names. For example, since end is a jq keyword, you would have to write:

{ "end": .end}

至少有一个名为 end的键使用现存的jq版本。

for a key named "end", at least using extant versions of jq.

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