如何使用Shell脚本在两个不同目录中比较具有相同名称的文件 [英] How to compare files with same names in two different directories using a shell script

问题描述

在继续使用SVN之前，我曾经通过简单地保存 / develop / 目录并在其中编辑和测试文件，然后将其移动到 / main / 目录。当我决定迁移到SVN时，我需要确保目录确实是同步的。

Before moving on to use SVN, I used to manage my project by simply keeping a /develop/ directory and editing and testing files there, then moving them to the /main/ directory. When I decided to move to SVN, I needed to be sure that the directories were indeed in sync.

因此，编写shell脚本的好方法是什么[bash ]来递归地比较两个不同目录中具有相同名称的文件？

So, what is a good way to write a shell script [ bash ] to recursively compare files with the same name in two different directories?

注意：上面使用的目录名称仅用于示例。我不建议将代码存储在顶层：）。

Note: The directory names used above are for sample only. I do not recommend storing your code in the top level :).

推荐答案

diff命令具有-r选项以递归比较目录：

The diff command has a -r option to recursively compare directories:

diff -r /develop /main

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