从差异输出中删除已删除的行 [英] Excluding deleted lines from diff output

问题描述

我有一些我不想引用的原始数据，但是我确实希望能够打补丁。如果我在文件中使用diff -u完全用其他内容替换了它的内容，而不是基本上得到全部删除和所有新行，而是在每行之前使用-得到了整个旧文件。

I have some original data that I do not want to reference, but I do want to be able to patch. If I use diff -u on a file where I entirely replaced its contents with something else, instead of getting basically a 'delete all' plus all the new lines, I get the whole old file with '-' before each line.

我们可以假设原始数据暂时没有变化。

We can assume the original data doesn't change for the moment. Is there a way to get diff to make a patch without duplicating any of the original data with '-' lines, i.e., have it just describe line numbers to delete along the way, and then all the insertions?

推荐答案

对 diff -e 选项$ c>和补丁，而不是 -u 。

这篇关于从差异输出中删除已删除的行的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！