遍历文件夹，然后遍历子文件夹并打印具有文本文件路径的文件名 [英] Iterate through folders, then subfolders and print filenames with path to text file

问题描述

我正在尝试使用python创建批量运行某些其他软件所需的文件。
为此，我需要生成一个文本文件，将所需的数据文件加载到软件中。
我的问题是我需要输入此文本文件的文件存储在一组结构化文件夹中。

I am trying to use python to create the files needed to run some other software in batch. For part of this I need to produce a text file that loads the needed data files into the software. My problem is that the files I need to enter into this text file are stored in a set of structured folders.

我需要遍历一组文件夹（最多20个），每个文件夹最多可以包含3个以上包含我需要的文件的文件夹。文件夹的最底层包含每次运行该软件所需的一组文件。文本文件应逐行打印这些文件的路径和名称，添加一条指令行，然后从文件夹移至下一组文件，依此类推，直到检查了所有子级文件夹。

I need to loop over a set of folders (up to 20), which each could contain up to 3 more folders which contain the files I need. The bottom level of the folders contain a set of files needed for each run of the software. The text file should have the path+name of these files printed line by line, add an instruction line and then move to the next set of files from a folder and so on until all of sub level folders have been checked.

推荐答案

使用os.walk（）。以下将输出 dir的子目录内的所有文件的列表。结果可以根据您的需要进行操作：

Use os.walk(). The following will output a list of all files within the subdirectories of "dir". The results can be manipulated to suit you needs:

import os                                                                                                             
                                                                                                                      
def list_files(dir):                                                                                                  
    r = []                                                                                                            
    subdirs = [x[0] for x in os.walk(dir)]                                                                            
    for subdir in subdirs:                                                                                            
        files = os.walk(subdir).next()[2]                                                                             
        if (len(files) > 0):                                                                                          
            for file in files:                                                                                        
                r.append(os.path.join(subdir, file))                                                                         
    return r                                                                                                          

对于python 3，将 next（）更改为 __ next __（）。

For python 3, change next() to __next__().

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