zip主文件夹，内部有子文件夹 [英] zip main folder with sub folder inside

问题描述

我有一个文件夹，里面有一些文件和子文件夹。我将如何读取目录并压缩主文件夹？

I have a folder with some files and sub folder inside. How im going to read the directory and zip the main folder?

例如：

maindirectory
--- file 1
--- file 2
--- subdirectory 1
------ file 3
------ file 4
--- subdirectory 2
------ file 5
------ file 6

我正在使用此脚本：

function Zip($source, $destination, $include_dir = false)
{

    if (!extension_loaded('zip') || !file_exists($source)) {
        return false;
    }

    if (file_exists($destination)) {
        unlink ($destination);
    }

    $zip = new ZipArchive();
    if (!$zip->open($destination, ZIPARCHIVE::CREATE)) {
        return false;
    }
    $source = str_replace('\\', '/', realpath($source));

    if (is_dir($source) === true)
    {

        $files = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($source), RecursiveIteratorIterator::SELF_CHILD);

        if ($include_dir) {

            $arr = explode("/",$source);
            $maindir = $arr[count($arr)- 1];

            $source = "";
            for ($i=0; $i < count($arr) - 1; $i++) { 
                $source .= '/' . $arr[$i];
            }

            $source = substr($source, 1);

            $zip->addEmptyDir($maindir);

        }

        foreach ($files as $file)
        {
            $file = str_replace('\\', '/', $file);

            // Ignore "." and ".." folders
            if( in_array(substr($file, strrpos($file, '/')+1), array('.', '..')) )
                continue;

            $file = realpath($file);

            if (is_dir($file) === true)
            {
                $zip->addEmptyDir(str_replace($source . '/', '', $file . '/'));
            }
            else if (is_file($file) === true)
            {
                $zip->addFromString(str_replace($source . '/', '', $file), file_get_contents($file));
            }
        }
    }
    else if (is_file($source) === true)
    {
        $zip->addFromString(basename($source), file_get_contents($source));
    }

    return $zip->close();
}

我这样调用该函数：

Zip('image/data/','aaa.zip',false);

但是我得到的是它压缩了整个 C：文件夹。我想要的只是将文档压缩在 image / data / 文件夹内。

But what I get is it zip the whole C: folder. What I want is to only zip document inside the image/data/ folder.

如何格式化正确的目录及其子目录？

How can I format the correct directory and it's subdirectories?

推荐答案

尝试一下。

zipFile('image/data/','aaa.zip', true);

/**
 * function zipFile.  Creates a zip file from source to destination
 *
 * @param  string $source Source path for zip
 * @param  string $destination Destination path for zip
 * @param  string|boolean $flag OPTIONAL If true includes the folder also
 * @return boolean
 */
function zipFile($source, $destination, $flag = '')
{
    if (!extension_loaded('zip') || !file_exists($source)) {
        return false;
    }

    $zip = new ZipArchive();
    if (!$zip->open($destination, ZIPARCHIVE::CREATE)) {
        return false;
    }

    $source = str_replace('\\', '/', realpath($source));
    if($flag)
    {
        $flag = basename($source) . '/';
        //$zip->addEmptyDir(basename($source) . '/');
    }

    if (is_dir($source) === true)
    {
        $files = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($source), RecursiveIteratorIterator::SELF_FIRST);
        foreach ($files as $file)
        {
            $file = str_replace('\\', '/', realpath($file));

            if (is_dir($file) === true)
            {
                $zip->addEmptyDir(str_replace($source . '/', '', $flag.$file . '/'));
            }
            else if (is_file($file) === true)
            {
                $zip->addFromString(str_replace($source . '/', '', $flag.$file), file_get_contents($file));
            }
        }
    }
    else if (is_file($source) === true)
    {
        $zip->addFromString($flag.basename($source), file_get_contents($source));
    }

    return $zip->close();
}

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