使用uuid字段进行Django迁移会生成重复的值 [英] Django migration with uuid field generates duplicated values
问题描述
我有一个 uuid
字段(不是主键)。生成的迁移是:
I have a uuid
field (not a primary key). The generated migration is:
from __future__ import unicode_literals
from django.db import migrations, models
import uuid
class Migration(migrations.Migration):
dependencies = [
....
]
operations = [
...
migrations.AddField(
model_name='device',
name='uuid',
field=models.UUIDField(default=uuid.uuid4, unique=True),
),
...
]
但是在执行 python manage.py migration
时,它崩溃了:
But when doing python manage.py migrate
it is crashing with:
django.db.utils.IntegrityError:无法创建唯一索引
restaurants_device_uuid_key详细信息:密钥
(uuid)=(f3858ded-b8e0-4ac0-8436
django.db.utils.IntegrityError: could not create unique index "restaurants_device_uuid_key" DETAIL: Key (uuid)=(f3858ded-b8e0-4ac0-8436-8a61b10efc73) is duplicated.
奇怪的是,主键似乎没有出现问题(可能是c
Strangely enough, the problem does not seem to occur with primary keys (which are maybe created by the database, and not internally by django?)
如何添加uuid字段并确保迁移有效?
How can I add a uuid field, and make sure that migrations work?
推荐答案
在此示例中,由于有了RunPython调用,一次迁移即可完成所有操作。
Here is an example doing everything in one single migration thanks to a RunPython call.
# -*- coding: utf-8 -*
from __future__ import unicode_literals
from django.db import migrations, models
import uuid
def create_uuid(apps, schema_editor):
Device = apps.get_model('device_app', 'Device')
for device in Device.objects.all():
device.uuid = uuid.uuid4()
device.save()
class Migration(migrations.Migration):
dependencies = [
('device_app', 'XXXX'),
]
operations = [
migrations.AddField(
model_name='device',
name='uuid',
field=models.UUIDField(blank=True, null=True),
),
migrations.RunPython(create_uuid),
migrations.AlterField(
model_name='device',
name='uuid',
field=models.UUIDField(unique=True)
)
]
这篇关于使用uuid字段进行Django迁移会生成重复的值的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!