在Django管理索引页面中定义自定义app_list [英] Defining a custom app_list in django admin index page

问题描述

我想定义一个自定义应用程序列表，以便在django的管理索引页面中使用，因为我希望这些应用程序以特定的顺序显示，而不是默认的字母顺序。遍历各种SO职位似乎似乎无法在任何明显的地方（例如admin.py，models.py）声明所需的应用程序顺序。

I'd like to define a custom application list to use in django's admin index page because I want the apps displayed in a specific order, rather than the default alphabetical order. Trawling through various SO posts it would appear that it's not yet possible to declare the desired application order in any of the obvious places (e.g. admin.py, models.py).

现在，我可以看到django管理员的index.html文件包含以下语句：

Now, I can see that the django admin's index.html file contains the following statement:

{% for app in app_list %}
   # do stuff with the app object

做东西，所以我想将其更改为使用名为my_app_list的自定义列表对象。在python中，我将按照以下步骤进行操作：

So I'd like to change this to use a custom list object called, say, my_app_list. In python I'd do this along the following lines:

from django.db.models import get_app
my_app_list = [get_app('myapp1'), get_app('myapp2'), ..., get_app('django.contrib.auth')]
for app in my_app_list
   ...

然后我的问题是，如何将上述前两行的等效代码编码到我的index.html本地副本中文件？

My question then is, how do I code the equivalent of the first 2 lines above into my local copy of the index.html file?

或者，或者，我应该将这些行插入哪个python源文件中，以便变量my_app_list在index.html中可用。

Or, alternatively, what python source file should I insert those lines into such that the variable my_app_list is available within index.html.

预先感谢。

Phil

推荐答案

子类 django.contrib.admin.site.AdminSite（）。覆盖 .index（）方法，然后执行以下操作：

Subclass django.contrib.admin.site.AdminSite(). Override the .index() method, and do something like this:

class MyAdminSite(django.contrib.admin.site.AdminSite):
    def index(self, request, extra_context=None):
        if extra_context is None:
            extra_context = {}
        extra_context["app_list"] = get_app_list_in_custom_order()
        return super(MyAdminSite, self).index(request, extra_context)

使用 my_admin_site = MyAdminSite（）实例化该子类的实例，将模型附加到该实例上（使用通常的 my_admin_site.register（）），并将其附加到URLconf；

Instantiate an instance of this subclass with my_admin_site = MyAdminSite(), attach your models to it (using the usual my_admin_site.register()), and attach it to the URLconf; that should do it.

（我没有尝试过，我只是基于对AdminSite源代码的阅读。）

(I haven't tried this, I'm basing this on my reading of the AdminSite source.)

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