如何获取Django中两个查询集的区别？ [英] How to get the difference of two querysets in Django?

问题描述

我必须查询集。所有列表和订阅列表

I have to querysets. alllists and subscriptionlists

alllists = List.objects.filter(datamode = 'A')
subscriptionlists = Membership.objects.filter(member__id=memberid, datamode='A')

我需要一个名为unsubscriptionlist的查询集拥有所有列表中的所有记录，但订阅列表中的记录除外。如何实现这一目标？

I need a queryset called unsubscriptionlist, which possess all records in alllists except the records in subscription lists. How to achieve this?

推荐答案

自Django 1.11开始，QuerySets就有了 difference（） 方法以及其他新方法：

Since Django 1.11, QuerySets have a difference() method amongst other new methods:

# Capture elements that are in qs_all but not in qs_part
qs_diff = qs_all.difference(qs_part)    

另请参阅： https：// stackoverflow .com / a / 45651267/5497962

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