将参数传递给Django模板中的模型方法 [英] Passing arguments to model methods in Django templates

问题描述

我正在尝试从指定的业务中获取所有客户，但是Customer模型中有一个类方法可基于同一业务获取一些信息...让我用代码来解释一下...

I'm trying to get all customers from a specified business, but there is a class method in Customer model to get some information based on the same Business... Let me explain this with code...

class Business(models.Model):
    ...
    customers = models.ManyToManyField(Customer, blank=True, null=True)

class Customer(models.Model):
    ...
    def get_something(self, obj_business)
        ...

好的，现在在我看来，我从这样的指定企业获得了所有客户：

Ok now in my views I get all customers from a specified business like this:

obj_customers = obj_business.customers.all()

然后我尝试将其打印在模板中：

Then I try to print this in my template:

{% for obj_customer in obj_customers %}
    {{ obj_customer.get_something ....... }}

但是是的，没有办法传递参数...我想知道是否缺少某些东西...

But yes, there is not a way to pass arguments... I would like to know if there is something that I'm missing...

I想知道是否还有另一种解决方案而不是创建模板标签...因为它是ManyToManyField，如果 customers 字段只是ForeignKey，则不需要将参数传递给该方法...

I wonder if there is another solution instead creating a template tag... because it is a ManyToManyField, if customers field had been just ForeignKey, no need to pass an argument to that method...

推荐答案

您可以创建一个简单的模板标签来调用带有任何参数的任何方法：

You can create a simple template tag to call any method with any arguments:

from django import template

register = template.Library()

@register.simple_tag
def call_method(obj, method_name, *args):
    method = getattr(obj, method_name)
    return method(*args)

然后在您的模板中：

{% call_method obj_customer 'get_something' obj_business %}

但是，当然，创建专用模板标签的安全性更高：-）

But, of course, crating of a specialized template tag is more safe :-)

@register.simple_tag
def get_something(customer, business):
    return customer.get_something(business)

模板：

{% get_something obj_customer obj_business %}

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