django admin,使用自定义视图扩展admin [英] django admin, extending admin with custom views

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问题描述

我想在这件事上寻求帮助。



我关注了指南可向我的管理员添加视图。



我使用的是网站使用的相同代码,但出现错误:



带有参数'的'app_list'的反向()和关键字参数'{'app_label':'reports'}'未找到。



admin / my_view 可以正常工作,但是如果我尝试访问管理员的其他页面(例如索引页面),则会收到错误消息



这是代码:

 #someapp / admin.py 

来自django.conf.urls导入模式
从django.contrib导入管理员
从django.http导入HttpResponse

def my_view(request):
return HttpResponse( Hello!)

def get_admin_urls(urls):
def get_urls():
my_urls =模式('',
(r'^ my_view / $',admin.site.admin_view(my_view))

返回my_urls + urls
return get_urls

admin_urls = get_admin_urls(admin.site.get_urls())
admin.site.get_urls = admin_urls

我正在使用django 1.8.2,python 2.7



还有,在管理员的索引页面中添加某些视图或上下文的最佳方法是什么? / p>

更新



我尝试了Antoine Pinsard的回答并尝试了以下方法:

 #admin.py 
来自django.contrib.admin import AdminSite
class MyAdminSite(AdminSite):

def get_urls(self):django.conf.urls中的
导入url
urls = super(MyAdminSite,self).get_urls()
urls == [
url(r'^ my_view / $',self.admin_view(self.my_view))
]
返回URL

def my_view(self,request):
返回HttpResponse( Hello !)

admin_site = MyAdminSite()

并替换urls.py url(r'^ admin /',include(admin.site.urls)), url(r'^ admin /',include( admin_site.urls)),



并获取:



带有参数'()'和关键字参数的'app_list'反向



回溯:

 请求方法:GET 
请求URL:http:// localhost:8000 / @ dmin /

Django版本:1.8.2
Python版本:2.7.10
已安装的应用程序:
('grappelli',
'django.contrib.admin',
'django.contrib.auth',
'django.contrib.contenttypes',
'django.contrib.sessions',
'django.contrib.messages',
'django.contrib.staticfiles',
'django.contrib.sessions.models',
'frontend',
'file_maintenance',
'reports',
'transactions',
'admin_reorder ',
'admin_notifications',
'django_twilio',
'daterange_filter')
已安装的中间件:
('django.contrib.sessions.middleware.SessionMiddleware',
'django.contrib.auth.models.User',
'django.middleware.common.CommonMiddleware',
'django.middleware.csrf.CsrfViewMiddleware',
'django.contrib.auth.middleware.AuthenticationMiddleware',
'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
'django.contrib.messages.middleware.MessageMiddleware',
'django.middleware.clickjacking.XFrameOptionsMiddleware',
'django.middleware.security.SecurityMiddleware',
'admin_reorder.middleware.ModelAdminReorder ')


追溯:
文件 C:\Python27\lib\site-packages\django\core\handlers\base.py在get_response
157中。response = middleware_method(request,response)
process_template_response
中的文件 C:\Python27\lib\site-packages\admin_reorder\middleware.py 134. self.init_config(request,app_list)
文件 C:\Python27\lib\site-packa init_config
21.中的ges\admin_reorder\middleware.py。admin_index = admin.site.index(request)
文件 C:\Python27\lib\site-packages\django _wrapped_view_func
57中的 viewsdecorators\cache.py。response = view_func(request,* args,** kwargs)
文件 C:\Python27\lib\site -packages\django\contrib\admin\sites.py,位于索引
438中。current_app = self.name,
文件 C:\Python27\lib\site\packages jandjango\core\urlresolvers.py反过来
579。return force_text(iri_to_uri(resolver._reverse_with_prefix(view,prefix,* args,** kwargs)))
文件 C: _reverse_with_prefix
496中的 Python27库站点包 django核心 urlresolvers.py。(lookup_view_s,args,kwargs,len(模式),模式))

异常类型:NoReverseMatch at / @ dmin /
异常值:带有参数'()'和关键字参数'{'app_label':'django_twilio'}'n的'app_list'的反向找不到。尝试了0个模式:[]


解决方案

本指南看起来很老我建议您遵循 django docs



someapp / admin.py



<从django.contrib.admin中导入pre> 从django中导入AdminSite
.http导入HttpResponse

class MyAdminSite(AdminSite):

def get_urls(self):来自django.urls的
导入路径
urls = super()。get_urls()
urls + = [
path('my_view /',self .admin_view(self.my_view))
]
返回网址

def my_view(自身,请求):
return HttpResponse( Hello!)

admin_site = MyAdminSite()

来源: https://github.com/django/django/blob/2.2/django/ contrib / admin / sites.py#L194-L205



您还应该更新您的 project / urls.py 并替换 path('admin /',admin.site.urls)通过 path('admin /',admin_site.urls)。不要忘记之前从someapp.admin导入admin_site


I would like to request some assistance regarding this matter.

I have followed this guide to add a view to my admin.

I am using the same code that the site has and I'm getting an error:

Reverse for 'app_list' with arguments '()' and keyword arguments '{'app_label': 'reports'}' not found.

The admin/my_view works fine but if I try to access the other pages in the admin such as the index page I am getting the error

Here's the code:

#someapp/admin.py

from django.conf.urls import patterns
from django.contrib import admin
from django.http import HttpResponse

def my_view(request):
    return HttpResponse("Hello!")

def get_admin_urls(urls):
    def get_urls():
        my_urls = patterns('',
            (r'^my_view/$', admin.site.admin_view(my_view))
         )
        return my_urls + urls
    return get_urls

admin_urls = get_admin_urls(admin.site.get_urls())
admin.site.get_urls = admin_urls

I am using django 1.8.2, python 2.7

also, what is the best way to add some view or context in the admin's index page?

UPDATE

I have tried Antoine Pinsard's answer and tried this:

#admin.py
from django.contrib.admin import AdminSite
class MyAdminSite(AdminSite):

    def get_urls(self):
        from django.conf.urls import url
        urls = super(MyAdminSite, self).get_urls()
        urls += [
            url(r'^my_view/$', self.admin_view(self.my_view))
        ]
        return urls

    def my_view(self, request):
        return HttpResponse("Hello!")

admin_site = MyAdminSite()

And replacing urls.py's url(r'^admin/', include(admin.site.urls)), to url(r'^admin/', include(admin_site.urls)),

and getting:

Reverse for 'app_list' with arguments '()' and keyword arguments

TRACEBACK:

Request Method: GET
Request URL: http://localhost:8000/@dmin/

Django Version: 1.8.2
Python Version: 2.7.10
Installed Applications:
('grappelli',
 'django.contrib.admin',
 'django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'django.contrib.sessions.models',
 'frontend',
 'file_maintenance',
 'reports',
 'transactions',
 'admin_reorder',
 'admin_notifications',
 'django_twilio',
 'daterange_filter')
Installed Middleware:
('django.contrib.sessions.middleware.SessionMiddleware',
 'django.contrib.auth.models.User',
 'django.middleware.common.CommonMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.auth.middleware.SessionAuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware',
 'django.middleware.security.SecurityMiddleware',
 'admin_reorder.middleware.ModelAdminReorder')


Traceback:
File "C:\Python27\lib\site-packages\django\core\handlers\base.py" in get_response
  157.                     response = middleware_method(request, response)
File "C:\Python27\lib\site-packages\admin_reorder\middleware.py" in process_template_response
  134.         self.init_config(request, app_list)
File "C:\Python27\lib\site-packages\admin_reorder\middleware.py" in init_config
  21.         admin_index = admin.site.index(request)
File "C:\Python27\lib\site-packages\django\views\decorators\cache.py" in _wrapped_view_func
  57.         response = view_func(request, *args, **kwargs)
File "C:\Python27\lib\site-packages\django\contrib\admin\sites.py" in index
  438.                                 current_app=self.name,
File "C:\Python27\lib\site-packages\django\core\urlresolvers.py" in reverse
  579.     return force_text(iri_to_uri(resolver._reverse_with_prefix(view, prefix, *args, **kwargs)))
File "C:\Python27\lib\site-packages\django\core\urlresolvers.py" in _reverse_with_prefix
  496.                              (lookup_view_s, args, kwargs, len(patterns), patterns))

Exception Type: NoReverseMatch at /@dmin/
Exception Value: Reverse for 'app_list' with arguments '()' and keyword arguments '{'app_label': 'django_twilio'}' not found. 0 pattern(s) tried: []

解决方案

This guide looks quite old. I would rather advise you to follow django docs.

someapp/admin.py

from django.contrib.admin import AdminSite
from django.http import HttpResponse

class MyAdminSite(AdminSite):

     def get_urls(self):
         from django.urls import path
         urls = super().get_urls()
         urls += [
             path('my_view/', self.admin_view(self.my_view))
         ]
         return urls

     def my_view(self, request):
         return HttpResponse("Hello!")

admin_site = MyAdminSite()

Source: https://github.com/django/django/blob/2.2/django/contrib/admin/sites.py#L194-L205

You should also update your project/urls.py and replace path('admin/', admin.site.urls) by path('admin/', admin_site.urls). Don't forget to from someapp.admin import admin_site before.

这篇关于django admin,使用自定义视图扩展admin的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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