正则表达式Django URL [英] Regex django url

问题描述

你好，我有一个网址，我想匹配uuid
，网址看起来像这样：

Hello I have a url and I want to match the uuid the url looks like this:

/ mobile / mobile-thing / 68f8ffbb-b715-46fb-90f8-b474d9c57134 /

urlpatterns = patterns("mobile.views",
    url(r'^$', 'something_cool', name='cool'),
    url(r'^mobile-thing/(?P<uuid>[.*/])$', 'mobile_thing', name='mobile-thinger'),
)

但这根本不起作用。我的对应观点没有被调用。我测试了很多变化... ahw

but this doesn't work at all. My corresponding view is not being called. I tested so many variations...ahw

但是 url（r'^ mobile-thing /'，' mobile_thing'，name ='mobile-thinger'）就像一个咒语，但没有任何组合...

but url(r'^mobile-thing/', 'mobile_thing', name='mobile-thinger') works like a charm but no group...

推荐答案

[。* /] 表达式仅匹配一个字符，可以是。， * 或 / 。您需要改写（这只是许多选项之一）：

The [.*/] expression only matches one character, which can be ., * or /. You need to write instead (this is just one of many options):

urlpatterns = patterns("mobile.views",
    url(r'^$', 'something_cool', name='cool'),
    url(r'^mobile-thing/(?P<uuid>[^/]+)/$', 'mobile_thing', name='mobile-thinger'),
)

这里， [^ /] 表示除 / 和 + 之后一次或多次匹配此类字符。您不希望最后的 / 放在 uuid var中，因此请将其放在括号之外。

Here, [^/] represents any character but /, and the + right after matches this class of character one or more times. You do not want the final / to be in the uuid var, so put it outside the parentheses.

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