Django：如何迁移在运行时制作的动态模型 [英] Django: How to migrate dynamic models made at runtime

问题描述

在我的Django应用中，特定的用户输入将导致创建新模型。这是我用来创建模型并注册它的代码。

In my Django app, a specific user input will result in the creation of a new model. Here is the code I am using to create the model and register it.

model = type(model_name, (ExistingModel,), attrs)
admin.site.register(model, admin_options)

from django.core.urlresolvers import clear_url_caches
from django.utils.module_loading import import_module
reload(import_module(settings.ROOT_URLCONF))
clear_url_caches()

此操作成功创建了新模型，但是，当我单击模型以查看管理页面上的表时，出现以下错误：

This successfully creates the new model, however, when I click on the model to see the table on the admin page, I get the following error:

relation ExistingModel_NewModel确实不存在

relation "ExistingModel_NewModel" does not exist

这通常意味着新模型更改尚未迁移。如何在Django中迁移动态创建的模型以查看其相应的数据表？

This usually means that the new model changes have not been migrated. How can I migrate dynamically created models in Django to see their corresponding data tables?

推荐答案

一个简单的解决方案对我有用。在创建动态模型之后，我最终像这样运行了 makemigrations 和 migrate 管理命令：

A simple solution worked for me. I ended up running the makemigrations and migrate management commands like so, after creating the dynamic model:

from django.core.management import call_command
call_command('makemigrations')
call_command('migrate')

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