没有Django模型的石墨烯Django？ [英] Graphene Django without Django Model?

问题描述

我已成功使用Graphene-Django成功构建了多个GraphQL调用。在所有这些情况下，我全部或部分填充Django模型，然后返回填充的记录。

I've successfully used Graphene-Django to successfully build several GraphQL calls. In all of those cases I populated, in whole or in part, a Django model and then returned the records I populated.

现在，我遇到了一种情况返回一些我不希望存储在Django模型中的数据。

Now I have a situation where I'd like to return some data that I don't wish to store in the Django model. Is this possible to do with Graphene?

Robert

推荐答案

Robert_LY在评论中完美地回答了他自己的问题，我想扩展他的解决方案。

Robert_LY answered his own question perfectly in the comments, I'd just like to expand his solution.

我的无数据库模型WordForm是自动生成的，而无需将其存储在数据库中。我将其定义为Django模型，如下所示：

My database-less model WordForm is generated automatically, without storing it in a database. I define it as a Django model as follows:

from django.db import models
class WordForm(models.Model):
    value = models.CharField(max_length=100)
    attributes = models.CharField(max_length=100)

在模式中，我定义节点并进行如下查询：

In the schema I define the node and query like this:

class WordFormNode(DjangoObjectType):
    class Meta:
        model = WordForm
        interfaces = (relay.Node, )

class Query(AbstractType):
    word_forms = List(WordFormNode,query=String(),some_id=String())

    def resolve_word_forms(self, args, context, info):
        query= args['query']
        some_id = from_global_id(args['some_id'])[1]
        word_forms = []
        # some logic to make WordForm objects with
        # WordForm(value=value,attributes=attributes),
        # then append them to list word_forms
        return word_forms

您可以根据需要向列表传递任意数量的参数，并以resolve_word_forms形式访问它们。

You can pass as many arguments as you like to the List and access them in resolve_word_forms.

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