在Django中，我如何编写url.py，其中users / self /与users /< pk> /相同，而< pk>是您登录的用户pk？ [英] In Django, how do I write a url.py where users/self/ is the same as users/<pk>/, where <pk> is your logged in user pk?

问题描述

我正在尝试编写一个 url.py ，其中有一个供用户

I am trying to write a url.py where I have a simple view for users

urlpatterns = patterns( 'doors.view',
    url( r'^users/$'            , 'users_list'  , name = 'users_list'   ),
    url( r'^users/(?P<pk>\d+)/$', 'users_detail', name = 'users_detail' ),
    url( r'^users/self/$'       , # do some sort of redirect here       ),
)

重定向的问题是我不知道 url.py 中已登录用户的 pk 。在 view.py 中，我显然会执行 @login_required 才能访问用户/ self / 。

The problem with the redirect is I don't know the pk of the logged in user in url.py. In view.py, I would obviously do a @login_required to be able to access users/self/.

也许我是用这种错误的方式？你们建议我做什么？

Maybe I am doing this wrong way? What do you guys suggest I do?

推荐答案

我的建议（不确定是否最简单的建议）是创建一个新的建议。视图，您可以在其中获取用户的pk，然后调用 users_detail 视图：

My suggestion (not sure if it's the easiest one) would be to create a new view, where you can grab the user's pk and then call the users_detail view:

@login_required
def self_detail(request):
    return users_detail(request, request.user.pk)

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