在Django中清除时如何更改另一个字段值？ [英] How to change another field value when Clear in Django?

问题描述

我正在使用Django表单更新，但面临一个小问题，我在表单更新中有3个字段，名称，图像，状态，现在，如果用户上传表单中的图像，则状态会自动更改为数据库中的 1 。

I am working with Django form Updation, but I am facing a small issue, I have 3 fields in form updating, name, image, status, Now if a user uploads an image in the form then the status is automatically changing to 1 in the database.

但是现在，如果我使用复选框，则此状态应该在我的数据库中更新为 0

but now if I clear the form using checkbox of the image then this status should be updated 0 in my database

这是我的 forms.py 文件...

class UpdateForm(forms.ModelForm):
...
def save(self, commit=True):
    instance = super(UpdateForm, self).save(commit=False)

    # Set status if saving picture
    if instance.image:
        instance.status = 1

    if commit:
        instance.save()

这是我的 views.py 文件...

def myview(request, id):
    datas=Product.objects..get(pk=id)
    form = UpdateForm(instance=datas)
    if request.method === 'POST'
       form = UpdateForm(request.POST or None, request.FILES or None, instance=datas)
       if form.is_valid():
         edit = form.save(commit=False)
         edit.save()
         return HttpResponse('Success')
    else:
      return HttpResponse('Fail')
    template_name='test.html'
    context={'datas':datas}
    return render(request, template_name, context)

这是我的 site.html 文件...

<form method="POST" action="" enctype="multipart/form-data">
  {% csrf_token %}
<a href="/media/{{datas.image}}"/>{{datas.image}}</a>
<input type="checkbox" name="image-clear" id="image-clear_id"/> Clear
<input type="submit" value="submit">

当我更新此表单时，它会更新状态中的 1 字段，但如果我从表单中清除，则 status 的状态应为 0 在我的数据库中

When I update this form then it updates 1 in the status field, but if I clear from form then status should be 0 in my database

推荐答案

通过取消选中复选框运行代码时，将跳过以下行：

When you run the code by unchecking the checkbox, the following line will be skipped:

if instance.image:
    instance.status = 1  # This will be skipped since instance.image is now False

尝试为instance.image条件为false时添加操作。

Try adding an action for when the condition for instance.image is false.

if instance.image:
    instance.status = 1
else:
    instance.status = 0

您当然可以对其进行重构，使其更加优美，但是清楚地表明了逻辑。

You can of course refactor that to write it more elegantly but that clearly shows the logic.

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